我正在为我的Jenkins管道使用extendedChoice插件。它从存储桶中获取s3对象,并使用简短的Groovy脚本提供值列表。问题是我需要使用管道的“环境”部分中定义的相应变量来对s3存储桶进行参数化。我该怎么办?
所以我尝试了很多不同的代码片段来获取env var,但是没有结果。
import jenkins.model.*
// This will print out the requested var from the global Jenkins config.
def envVars = Jenkins.instance.getGlobalNodeProperties()[0].getEnvVars()
return envVars['S3_BUCKET']
// This will print out values from the env vars of the node itself where the Jenkins is running.
def env = System.getenv('S3_BUCKET')
return env
// This is what I have now
def domainsList = "aws s3api list-objects-v2 --bucket someRandomBucket --output text --delimiter /".execute() | 'cut -d / -f 1'.execute() | 'sed 1d'.execute()
domainsList.waitFor()
def output = domainsList.in.text
return output.split('COMMONPREFIXES')
// This is the Jenkinsfile
pipeline {
agent any
environment {
DOMAIN_NAME = "${params.DOMAIN_NAME}"
MODEL_VERSION = "${params.MODEL_VERSION}"
S3_BUCKET = "someRandomBucket"
}
parameters {
extendedChoice(
bindings: '',
defaultValue: '',
description: '',
descriptionPropertyValue: '',
groovyClasspath: '',
groovyScript: '''
def domainsList = "aws s3api list-objects-v2 --bucket someRandomBucket --output text --delimiter /".execute() | 'cut -d / -f 1'.execute() | 'sed 1d'.execute()
domainsList.waitFor()
def output = domainsList.in.text
return output.split('COMMONPREFIXES')
''',
multiSelectDelimiter: ',',
name: 'DOMAIN_NAME',
quoteValue: false,
saveJSONParameterToFile: false,
type: 'PT_SINGLE_SELECT',
visibleItemCount: 10)
choice(
choices: ['a', 'b'],
description: 'Select a model version for processing',
name: 'MODEL_VERSION')
}
stages {
stage('Clean workdir') {
steps {
cleanWs()
}
}
stage('build') {
steps {
sh "echo $S3_BUCKET"
sh "echo $DOMAIN_NAME"
sh "echo $MODEL_VERSION"
}
}
}
}
如上所述,我需要在groovy脚本的extendedChoice参数中用S3_BUCKET env var值替换someRandomBucket硬代码
已解决-可以通过Jenkins作业UI专门为参数注入环境变量