Am使用Spring Security在Spring MVC&JPA中开发应用程序。现在通过LDAP集成OUD(Oracle统一目录)。在进行用户身份验证时,来自OUD日志文件中LDAP的响应是
CONNECT conn = 909681从*******到*******:1636 protocol = LDAPS
绑定REQ conn = 909681 op = 0 msgID = 1 type = SIMPLE dn =“” version = 3
BindRES conn = 909681 op = 0 msgID = 1 result = 1 message =“目录服务器找不到绑定dn”“的网络组,因为客户端连接与连接不匹配网络组的标准。”
断开连接 conn = 909681原因=“客户端断开连接”
security.xml文件中的应用程序和LDAP之间的映射
<bean id="contextSource" class="org.springframework.security.ldap.DefaultSpringSecurityContextSource">
<constructor-arg value="ldaps://192.168.0.182:1636/o=company"/>
<property name="userDn" value="cn=userid,o=company,ou=groups"/>
<property name="password" value="password"/>
</bean>
<bean id="ldapAuthProvider" class="org.springframework.security.ldap.authentication.LdapAuthenticationProvider" >
<constructor-arg>
<bean class="in.web.service.impl.CustomLdapBindAuthenticator">
<constructor-arg ref="contextSource"/>
<property name="userDnPatterns">
<list>
<value>cn={0},ou=groups</value>
</list>
</property>
</bean>
</constructor-arg>
<constructor-arg>
<bean class="in.web.service.impl.CustomLdapUserAuthoritiesPopulator">
</bean>
</constructor-arg>
</bean>
CustomLdapBindAuthenticator中的代码
public LdapUserDetails search(String cn) throws Exception {
Hashtable env = new Hashtable();
String sp = "com.sun.jndi.ldap.LdapCtxFactory";
env.put(Context.INITIAL_CONTEXT_FACTORY, sp);
String [] urls = contextSource.getUrls();
for(String url: urls){
System.out.println("ldapurls="+url);
}
env.put(Context.PROVIDER_URL, urls[0]);
DirContext dctx = new InitialDirContext(env);
String base = "ou=groups,o=company";
System.out.println("BASE DN="+base);
SearchControls sc = new SearchControls();
String[] attributeFilter = {"cn", "fullName", "mail", "l", "mobile"};
sc.setReturningAttributes(attributeFilter);
sc.setSearchScope(SearchControls.SUBTREE_SCOPE);
String filter = "(&(cn="+cn+")(objectClass=*))";
NamingEnumeration results = dctx.search(base, filter, sc);
LdapUserDetails user = new LdapUserDetails();
while (results.hasMore()) {
SearchResult sr = (SearchResult) results.next();
Attributes attrs = sr.getAttributes();
user.setCn(getAttribute(attrs, "cn"));
user.setFullName(getAttribute(attrs, "fullName"));
user.setMail(getAttribute(attrs, "mail"));
user.setMobile(getAttribute(attrs, "mobile"));
user.setLocation(getAttribute(attrs, "l"));
}
dctx.close();
return user;
}
Pl。帮我解决问题
预先感谢
答案 0 :(得分:1)
默认身份验证为“简单绑定”,表示DN和密码。
您没有在环境env
中设置任何凭据,因此JNDI会默认尝试进行绑定匿名操作,即空DN和密码。