Question

我正在做一些有关unsafe.Pointer的测试。假设TestFun是常见的库函数，那么“ Person”结构不应出现在该函数中

type Person struct {
    Name string
}

func main() {
    p := &Person{}
    p.Name = "TestName"
    TestFun(p)
}

func TestFun(val interface{}) {
    // I want to convert interface{} to unsafe.Pointer
    var pointer unsafe.Pointer

    // This Line compile error
    //pointer = unsafe.Pointer(val)

    // This is ok, but "Person" appears. This function is a common function, "Person" should not appear
    // pointer = unsafe.Pointer(val.(*Person))

    println(pointer)
}

我该怎么做？

Answer 1

使用unsafe.Pointer(val)代替unsafe.Pointer(&val)。因为它接受指针。

package main

import (
    "unsafe"

)
type Person struct {
    Name string
}

func main() {
    p := &Person{}
    p.Name = "TestName"

    TestFun(p)
}

func TestFun(val interface{}) {
    // I want to convert interface{} to unsafe.Pointer
    var pointer unsafe.Pointer

    pointer = unsafe.Pointer(&val)

    println(pointer)

    u := (*interface{})(pointer)
    p := (*u).(*Person)
    println(p.Name)
}

interface {}转换为unsafe.Pointer问题

1 个答案: