我只需要使用JavaScript
开始JSON结果
[
{"ID":1,"code":"AAA","modifieddate":"2019-06-01","user":"John"},
{"ID":2,"code":"AAA","modifieddate":"2019-06-02","user":"Jane"},
{"ID":3,"code":"AAA","modifieddate":"2019-06-03","user":"Sue"},
{"ID":4,"code":"BBB","modifieddate":"2019-06-10","user":"Rick"},
{"ID":5,"code":"CCC","modifieddate":"2019-06-11","user":"Joe"}
]
所需的JSON结果集
[
{"ID":3,"code":"AAA","modifieddate":"2019-06-03","user":"Sue","Count":"3"},
{"ID":4,"code":"BBB","modifieddate":"2019-06-10","user":"Rick","Count":"1"},
{"ID":5,"code":"CCC","modifieddate":"2019-06-11","user":"Joe","Count":"1"}
]
答案 0 :(得分:2)
您可以使用Array.reduce
对每个项目的code
属性的结果集进行分组,根据需要递增Count
,然后从累积对象中获取值。在此过程中,我们执行日期比较,以确定要在结果中包括哪个最新条目。
const data = [ {"ID":1,"code":"AAA","modifieddate":"2019-06-01","user":"John"}, {"ID":2,"code":"AAA","modifieddate":"2019-06-02","user":"Jane"}, {"ID":3,"code":"AAA","modifieddate":"2019-06-03","user":"Sue"}, {"ID":4,"code":"BBB","modifieddate":"2019-06-10","user":"Rick"}, {"ID":5,"code":"CCC","modifieddate":"2019-06-11","user":"Joe"} ];
const result = Object.values(data.reduce((a, e) => {
if (!a[e.code]) {
a[e.code] = {...e, Count: 0};
}
if (Date.parse(e.modifieddate) > Date.parse(a[e.code].modifieddate)) {
a[e.code] = {...e, Count: a[e.code].Count};
}
a[e.code].Count++;
return a;
}, {}));
console.log(result);
顺便说一下,这只是我们正在使用的普通JS数组,而不是JSON。
答案 1 :(得分:1)
这应该可以帮助您:
let array = [
{"ID":1,"code":"AAA","modifieddate":"2019-06-01","user":"John"},
{"ID":2,"code":"AAA","modifieddate":"2019-06-02","user":"Jane"},
{"ID":3,"code":"AAA","modifieddate":"2019-06-03","user":"Sue"},
{"ID":4,"code":"BBB","modifieddate":"2019-06-10","user":"Rick"},
{"ID":5,"code":"CCC","modifieddate":"2019-06-11","user":"Joe"}
]
let result = array.reduce(function(total, currentValue, currentIndex, arr) {
let index = total.findIndex(function(entry) { return entry.code == currentValue.code; })
if (index >= 0) { // entry already exists
// check modified
if (total[index].modifieddate > currentValue.modifieddate) { // already have most recent of the two
total[index].Count += 1;
} else { // need to replace with more recent
currentValue.Count = total[index].Count + 1;
total[index] = currentValue;
}
} else { // first record for this code
currentValue.Count = 1;
total.push(currentValue);
}
return total;
}, []);
console.log(result);
这是工作中的js-fiddle
注意:在代码块中进行注释