这是我的截击任务,我想将响应数据存储到arraylist。我在控制台中得到了整个结果,但是在arraylist中,它仅存储第一条记录
private void loadJsonArray() {
JsonArrayRequest jsArrayRequest = new JsonArrayRequest
(Request.Method.GET, obj_url, null, new Response.Listener<JSONArray>() {
Questions questions = new Questions();
ArrayList<Questions> contactLists = new ArrayList<>();
@Override
public void onResponse(JSONArray responseArray) {
try {
for (int i = 0; i < responseArray.length(); i++) {
JSONObject response = responseArray.getJSONObject(i);
Log.v("Naveen", response.toString());
questions.setId(response.getInt("employee_id"));
questions.setQuestions(response.getString("name"));
questions.setOption1(response.getString("dob"));
questions.setOption2(response.getString("designation"));
questions.setOption3(response.getString("contact_number"));
questions.setAnswerNr(response.getInt("email"));
questions.setDifficulty(response.getString("salary"));
contactLists.add(questions);
Log.v("Kumar", contactLists.toString());
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
//Display error message whenever an error occurs
Toast.makeText(getApplicationContext(),
error.getMessage(), Toast.LENGTH_SHORT).show();
}
});
// Access the RequestQueue through your singleton class.
MySingleton.getInstance(this).addToRequestQueue(jsArrayRequest);
}
和我的控制台:
06-12 00:45:22.863 6930-6930/com.codinginflow.myawesomequiz V/Naveen: {"employee_id":"1","name":"what is php","dob":"1994-08-28","designation":"Systems Engineer","contact_number":"8888888888","email":"1","salary":"easy"}
06-12 00:45:22.863 6930-6930/com.codinginflow.myawesomequiz V/Naveen: {"employee_id":"2","name":"what is html","dob":"1989-03-01","designation":"Technology Lead","contact_number":"7777777777","email":"2","salary":"easy"}
06-12 00:45:22.863 6930-6930/com.codinginflow.myawesomequiz V/Naveen: {"employee_id":"3","name":"what is java","dob":"1990-05-20","designation":"Technology Consultant","contact_number":"7888888888","email":"3","salary":"easy"}
06-12 00:45:22.864 6930-6930/com.codinginflow.myawesomequiz V/Naveen: {"employee_id":"4","name":"what is ip","dob":"1993-08-25","designation":"Systems Engineer","contact_number":"7999999999","email":"1","salary":"easy"}
06-12 00:45:22.864 6930-6930/com.codinginflow.myawesomequiz V/Naveen: {"employee_id":"3","name":"what is java","dob":"1990-05-20","designation":"Technology Consultant","contact_number":"7888888888","email":"3","salary":"easy"}
06-12 00:45:22.864 6930-6930/com.codinginflow.myawesomequiz V/Kumar: [com.codinginflow.myawesomequiz.Questions@2885909, com.codinginflow.myawesomequiz.Questions@2885909, com.codinginflow.myawesomequiz.Questions@2885909, com.codinginflow.myawesomequiz.Questions@2885909, com.codinginflow.myawesomequiz.Questions@2885909]
它只存储第一条记录,而多次,我如何将所有记录存储到arraylist中?
答案 0 :(得分:0)
我更喜欢每次循环。看起来比较干净。解决方案是您需要在所有迭代中创建新对象
for (Questions question: responseArray){
Questions questions = new Questions();
questions.setId(response.getInt("employee_id"));
questions.setQuestions(question.getString("name"));
questions.setOption1(question.getString("dob"));
questions.setOption2(question.getString("designation"));
questions.setOption3(question.getString("contact_number"));
questions.setAnswerNr(question.getInt("email"));
questions.setDifficulty(question.getString("salary"));
contactLists.add(questions);
答案 1 :(得分:0)
您好,您似乎一遍又一遍地重复使用相同的Questions
实例,这会导致列表中填充相同实例的重复项。每次填充对象时,尝试创建一个新实例:
for (int i = 0; i < responseArray.length(); i++) {
Questions questions = new Questions();
[...]
contactLists.add(questions);
}
答案 2 :(得分:0)
您应该在其中创建一个新的Questions对象-否则,您将覆盖之前创建的对象。
for (int i = 0; i < responseArray.length(); i++) {
Questions questions = new Questions();
JSONObject response = responseArray.getJSONObject(i);
Log.v("Naveen", response.toString());
questions.setId(response.getInt("employee_id"));
questions.setQuestions(response.getString("name"));
questions.setOption1(response.getString("dob"));
questions.setOption2(response.getString("designation"));
questions.setOption3(response.getString("contact_number"));
questions.setAnswerNr(response.getInt("email"));
questions.setDifficulty(response.getString("salary"));
contactLists.add(questions);
Log.v("Kumar", contactLists.toString());