Question

我有一个xml文件，我正在从中读取数据并尝试通过表单进行更新。我有一个书清单和一个“编辑”按钮，该按钮将书的ID传递到名为“ edit.php”的页面。 $ id变量已通过$ _GET正确传递（在测试页面上回显了$ id）。这是我尝试的方法，但是在下面的指示行中我仍然收到错误。这是我阅读xml的地方：

$xml = new DOMDocument('1.0', 'utf-8');
$xml->load('DATA/Books.xml');

$id = $_GET['id'];

//Get item Element
$book = $xml->getElementsByTagName('book')->item($id);

//Load child elements
$title= $book->getElementsByTagName('title')->item(0); //error here
$author= $book->getElementsByTagName('author')->item(0);

//Replace old elements with new
$book->replaceChild($title, $title);
$book->replaceChild($author, $author);
header('location:Books.php');
?>

我在这里处理提交表单：

<?php
if (isset($_POST['submit'])) {
    $title->nodeValue = $_POST['newTitle'];
    $author->nodeValue = $_POST['newAuthor'];
    htmlentities($xml->save('DATA/Books.xml'));
}
?>

这是我的表格：

<form class="form" method="post">
    <input type="text" name="newTitle" id="title" value="<?php echo $title->nodeValue;?>" class="form-control">
    <input type="text" name="newAuthor" id="author" value="<?php echo $author->nodeValue;?>" 
    <input type="submit" name="submit" class="btn btn-info btn-md" value="Update">
</form>

这是我的xml示例：

<?xml version="1.0" encoding="UTF-8"?>
<books>
    <book id="3"><title>Test</title><author>Test</author></book>
</books>

Answer 1

考虑构建所需的节点片段，然后将其导入主DOM。请参见下面的示例，您可以在其中将表单值调整到所需的位置：

$xml = new DOMDocument('1.0', 'utf-8');
$xml->preserveWhiteSpace = false;
$xml->formatOutput = true;

$xml->loadXML('<?xml version="1.0" encoding="UTF-8"?>
   <books>
      <book id="3">
         <title>Test</title>
         <author>Test</author>
      </book>
   </books>');

// Search Needed Path
$id = 3;    
$xpath = new DOMXpath($xml);
$nodelist = $xpath->query("/books/book[@id='$id']");    
$old_book = $nodelist->item(0);

// Create Fragment
$root = new DomDocument;
$new_book = $root->createElement('book');

$new_book->appendChild($root->createElement('title', 'my new title'));
$new_book->appendChild($root->createElement('book', 'my new book'));
$root->appendChild($new_book);

// Import Fragment
$new_book = $xml->importNode($root->documentElement, true);    
// Replace Old for New
$old_book->parentNode->replaceChild($new_book, $old_book);

echo $xml->saveXML();

https://docs.scrapy.org/en/latest/topics/request-response.html#scrapy.http.Request

输出

<?xml version="1.0" encoding="UTF-8"?>
<books>
  <book>
    <title>my new title</title>
    <book>my new book</book>
  </book>
</books>

通过PHP表单更新XML

1 个答案: