纸浆优化错误-LPVariable对象不支持索引

时间:2019-06-11 17:40:19

标签: python optimization pulp

当尝试添加位于第31行的约束时,我总是出错,模型+ =([[MAHL [i] [j] for(i,j)in yearhours)])<= 40

我不确定如何正确设置此约束。我想说的是,在i和j的每个索引处,特定值必须小于40,并针对所有i,j对执行该操作。

我对PULP并不陌生,他试图建立并运行基本模型。输入数据只是一堆随机值,它们的长度为365行,宽度为24列。

from pulp import *
import pandas as pd
import numpy as np
import xlrd

model = pulp.LpProblem("Basic Model", pulp.LpMaximize)

YPER = 365
HE = 24

yearlyhours = [(i,j) for i in range(YPER) for j in range(HE)]

xlsx = pd.ExcelFile('IvA.xlsx')
df1 = pd.read_excel(xlsx, 'Sheet5')
df2 = pd.read_excel(xlsx, 'Sheet3')
df3 = pd.read_excel(xlsx, 'Sheet2')

MAHL = pulp.LpVariable('MAHL', (YPER, HE), cat='Integer')
MALL = pulp.LpVariable('MALL', cat='Integer')
DAHL = pulp.LpVariable('DAHL', cat='Integer')
DALL = pulp.LpVariable('DALL', cat='Integer')

book = xlrd.open_workbook('IvA.xlsx')
sheet10 = book.sheet_by_name('Sheet10')
sheet11 = book.sheet_by_name('Sheet11')

DAPRICE = [[sheet10.cell_value(r, c) for c in range(sheet10.ncols)] for r in range(sheet10.nrows)]
LOAD = [[sheet11.cell_value(r, c) for c in range(sheet11.ncols)] for r in range(sheet11.nrows)]

#model += (MAHL[i][j] for i in range(YPER) for j in range(HE)) <= 40
model += ([MAHL[i][j] for (i,j) in yearlyhours]) <= 40

model += (pulp.lpSum([DAPRICE[i][j] * LOAD[i][j] for i in range(YPER) for j in range(HE)]))

model.solve()
pulp.LpStatus[model.status]
print("Status:", LpStatus[model.status])

obj = value(model.objective)
print(obj)

我尝试了几种解决方案,另外一种被注释掉了。

Traceback (most recent call last):
  File "bs.py", line 31, in <module>
    model += ([MAHL[i][j] for (i,j) in yearlyhours]) <= 40
  File "bs.py", line 31, in <listcomp>
    model += ([MAHL[i][j] for (i,j) in yearlyhours]) <= 40
TypeError: 'LpVariable' object does not support indexing

1 个答案:

答案 0 :(得分:3)

您已将MAHL定义为pulp.LpVariable,(由于错误状态)它不支持索引,因为它为LP变量建模。

您可能想使用pulp.LpVariable.dicts进行定义。

示例:

MAHL = pulp.LpVariable.dicts('MAHL', yearlyhours, cat=pulp.LpInteger)

并将其称为

model += pulp.lpSum([MAHL[(i,j)] for (i,j) in yearlyhours]) <= 40