Question

我有四个桌子。

BHD 选择 FTB DRM

我想从BHD获得列代理和状态，从OPT获得描述，从FTB获得booking_actual零售，从DRM获得analysis_master1。

BHD中的full_reference列链接到FTB.Reference，DRM.code链接到BHD.AGENT，OPT_ID链接到BHD_ID。

我尝试过：

DELETE FROM e78_posts WHERE id IN (SELECT a.post_id FROM ( SELECT MIN(meta_id) AS `meta_id` ,MIN(post_id) AS `post_id` FROM e78_postmeta WHERE meta_key='_sku' GROUP BY meta_value HAVING COUNT(*) > 1 ) a )
DELETE FROM e78_postmeta WHERE meta_id IN (SELECT a.meta_id FROM ( SELECT MIN(meta_id) AS `meta_id` ,MIN(post_id) AS `post_id` FROM e78_postmeta WHERE meta_key='_sku' GROUP BY meta_value HAVING COUNT(*) > 1 ) a )

并得到：

在FROM子句中多次指定了相关名称'bad'。

只是想知道我要去哪里错了，或者有人是否有更好的主意？

Answer 1

这应该有效

 SELECT bad.agent as agents,
 bad.status as thestatus,
 desc.description as product,
 retail.booking_actual_retail as actualretail,
 country.analysis_master1 as countries
 from BHD bad
 inner join FTB on ftb.booking_reference = bad.FULL_REFERENCE
 inner join DRM Country on bad.agent = country.code
 inner join OPT desc on bad.id = desc.id

Answer 2

SELECT bad.agent as Agents,
bad.status as TheStatus,
desc1.description as Product,
country.analysis_master1 as Country,
ftb.booking_actual_retail as ActualRetail,
ftb.Entered_Date
from BHD bad
inner join FTB on ftb.booking_reference = bad.FULL_REFERENCE
inner join DRM Country on bad.agent = country.code
inner join OPT desc1 on bad.BHD_ID = desc1.OPT_ID

整理来自四个表的数据时出现问题

2 个答案: