如何仅使用日期字段计算唯一的每日和每周启动日期？

Question

很抱歉，如果措辞不佳

我需要计算一周中每天启动的网站数量。我目前只有某天发射的东西-可以算作1次发射，并且需要在星期几使用。

我正在使用bigquery，因此必须使用我刚接触过的提取功能。

SELECT
count(Distinct PUBLISHED_DAY),
EXTRACT(DAY from PUBLISHED_DAY) as dow
EXTRACT(WEEK(SUNDAY) from PUBLISHED_DAY) as sunday
EXTRACT(WEEK(MONDAY from PUBLISHED_DAY) as monday
EXTRACT(WEEK(TUESDAY) from PUBLISHED_DAY) as tuesday
EXTRACT(WEEK(WEDNESDAY) from PUBLISHED_DAY) as WEDNESDAY 
EXTRACT(WEEK(THURSDAY) from PUBLISHED_DAY) as THURSDAY
EXTRACT(WEEK(FRIDAY) from PUBLISHED_DAY) as FRIDAY
EXTRACT(WEEK(SATURDAY) from PUBLISHED_DAY) as Saturday 
FROM[table] 

我遇到此错误，我也不知道这会返回按星期几计算的不同天数。  错误：在第3行第13列的“”处遇到了““ FROM”“，原为：”）“ ...

Answer 1

您在寻找这个吗？

SELECT EXTRACT(DAYOFWEEK FROM PUBLISHED_DAY) as dow, COUNT(*)
FROM t
GROUP BY dow;

Answer 2

  

我正在使用bigquery，所以我必须使用我刚接触过的提取功能。

EXTRACT函数在BigQuery Standard SQL（而不是Legacy SQL）中可用，该函数解释了在Legacy SQL中运行时看到的错误

因此，只需确保您是在Standard SQL中进行查询，例如

#standardSQL
SELECT
  EXTRACT(DAYOFWEEK FROM PUBLISHED_DAY) AS dow,
  .... 
FROM `project.dataset.table`   

Answer 3

考虑使用FORMAT_DATE('%A', PUBLISHED_DAY)代替提取。