我有一个表，需要检查是否存在多个<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
<meta http-equiv="X-UA-Compatible" content="ie=edge" />
<link rel="stylesheet" href="ticket.css" />
<title>Document</title>
</head>
<body>
<section class="section-ticket">
<div class="left">
<button class="left-button">Back</button>
<div class="event">
<div class="event-date">
Jan <br />
5
</div>
<h2>Soundcity MVP Award Festival</h2>
<h2>Eko Hotel, Victorial Island Lagos</h2>
<p>
Event description goes here and more description for other things
goes here and more and more so I cant say them all.
</p>
</div>
<div class="share">
<p>Share Event</p>
<i class="fas fas-facebook"></i>
</div>
</div>
<div class="right">
<div>
<h1>Hello</h1>
</div>
</div>
</section>
</body>
</html>
和不同的/* Base reset styles */
*,
*::before,
*::after {
padding: 0;
margin: 0;
box-sizing: inherit;
}
html {
font-size: 62.5%;
}
body {
box-sizing: border-box;
}
.section-ticket {
display: grid;
grid-template-columns: 1fr 1fr;
height: 100vh;
}
.left {
background-color: red;
padding: 5.9rem 5.4rem 6.5rem 10rem;
display: flex;
flex-direction: column;
align-items: flex-start;
/* position: relative; */
}
.right {
background-color: blue;
padding: 9.1rem 10rem 19.4rem 5.9rem;
}
.left-button {
background: #f5f5f5;
padding: 0.4rem 3rem;
font-size: 2rem;
cursor: pointer;
border: none;
outline: none;
margin-bottom: 8.3rem;
}
.event {
/* display: flex; */
/* flex-direction: column; */
/* justify-content: flex-start; */
/* width: 100%; */
}
.event-date {
/* display: flex; */
display: inline-block;
/* justify-content: flex-end; */
/* position: absolute; */
/* width: 100%; */
text-align: center;
text-transform: uppercase;
font-size: 2.5rem;
padding: 1rem 2.4rem;
background-color: #ffbb00;
box-shadow: 0 0 1.3rem rgba(0, 0, 0, 0.016);
margin-bottom: 2.3rem;
}
.event h2 {
font-size: 3.5rem;
margin-bottom: 1rem;
font-family: 'Helvetica';
}
.event p {
font-size: 2rem;
margin-bottom: 13.8rem;
}
.share {
font-size: 2rem;
}
，并返回只有个记录并且有{ ids列中的{1}}。
例如使用此表：
types我想返回以下结果：
ids由于这些只有一个包含试验的记录。如果trial包含试用和购买商品，我希望排除这些行。
答案 0 :(得分：1)
可以通过内部查询来完成
select * from t where id IN (select id from t group by id having count(*) <= 1) AND trial = 'trial';
答案 1 :(得分：0)
我认为您不想要存在
select t.*
from t
where t.type = 'trial' and
not exists (select 1 from t t2 where t2.id = t.id and t2.type <> 'trial');
如果您只想满足此条件的id，我建议进行汇总：
select t.*
from t
group by t.id
having sum( (t.type <> 'trial')::int ) = 0;
答案 2 :(得分：0)
使用JOIN的另一种选择。子查询将结果限制为唯一的id值，然后WHERE子句进一步将其过滤为您感兴趣的type值。
select
t.id,
t.type
from
@table as t
JOIN
(
select
id
from @table
group by id
having count(*)=1
) as d
on d.id = t.id
where type = 'trial';
返回问题中的结果集。