Question

awk if else语句中存在语法错误，该语句是我从另一个问题获取代码而无法修复的。 Bash one-liner code to output unique values。

有人可以更正此声明吗？

awk 'BEGIN {output=0} /Slave_IO_Running.*No/ {output+=1} /Slave_SQL_Running.*No/ {output +=2} END {if(output==3} {print 0} else {if(output==0} {print 3} else {print output}}'

调试输出

awk 'BEGIN {output=0} /Slave_IO_Running.*No/ {output+=1} /Slave_SQL_Running.*No/ {output +=2} END {if(output==3}{print 0} else {if(output==0} {print 3} else {print output}}'
awk: cmd. line:1: BEGIN {output=0} /Slave_IO_Running.*No/ {output+=1} /Slave_SQL_Running.*No/ {output +=2} END {if(output==3}{print 0} else {if(output==0} {print 3} else {print output}}
awk: cmd. line:1:                                                                                                           ^ syntax error
awk: cmd. line:1: BEGIN {output=0} /Slave_IO_Running.*No/ {output+=1} /Slave_SQL_Running.*No/ {output +=2} END {if(output==3}{print 0} else {if(output==0} {print 3} else {print output}}
awk: cmd. line:1:                                                                                                                      ^ syntax error
awk: cmd. line:1: BEGIN {output=0} /Slave_IO_Running.*No/ {output+=1} /Slave_SQL_Running.*No/ {output +=2} END {if(output==3}{print 0} else {if(output==0} {print 3} else {print output}}
awk: cmd. line:1:                                                                                                                                        ^ syntax error
awk: cmd. line:1: BEGIN {output=0} /Slave_IO_Running.*No/ {output+=1} /Slave_SQL_Running.*No/ {output +=2} END {if(output==3}{print 0} else {if(output==0} {print 3} else {print output}}
awk: cmd. line:1:                                                                                                                                                    ^ syntax error
awk: cmd. line:1: BEGIN {output=0} /Slave_IO_Running.*No/ {output+=1} /Slave_SQL_Running.*No/ {output +=2} END {if(output==3}{print 0} else {if(output==0} {print 3} else {print output}}
awk: cmd. line:1:                                                                                                                                                                       ^ syntax error

Answer 1

if(output==0}和if(output==3}应该以封闭括号)结尾，而不是封闭括号}。

对于嵌套的if语句，您应该使用else if，并且这些花括号仅对于多个操作是必需的。

END {if(output==3) print 0; else if(output==0) print 3; else print output}

只是为了好玩：

END {print output==3? 0: output==0? 3: output}

Answer 2

错误消息中有一些线索，例如：

awk: cmd. line:1: ... END {if(output==3}{print 0} else {if(output==0} {print 3} else {print output}}
awk: cmd. line:1:                      ^ syntax error

这真的很清楚。

awk if else语句语法错误。是什么原因造成的？

2 个答案: