当我实现从服务器返回的数据巫婆的分页ListView
时,我可以简单地测试此分页能力,并且可以很好地工作,例如,通过此代码,我可以使用简单数据创建列表列:
list.add(
PostItem((b) =>b
..title = 'lorem ipsum'
..colorInt = _randomGenerator.nextInt(0xFFFFFFFF)),
);
return BuiltList.of(list);
现在我正在尝试从服务器获取数据,并使用以下方法从中获取数据:
List<PostItem> list = [
PostItem((b)=>b..title = 'lorem ipsum'),
PostItem((b)=>b..title = 'lorem ipsum')
];
我收到错误消息:
List<PostItem> list=[];
final response = await http.get(Constants.getPosts, headers: {"Accept": "application/json"});
final responseString = json.decode(response.body) as List;
List<ContentsModel> responses = responseString.map((j) =>
ContentsModel.fromJson(j)).toList();
responses.map((post)=>
list.add(PostItem((b) => b..title = post.title),));
return BuiltList.of(list);
在此list
的行大小为零:
responses.map((post)=> list.add(PostItem((b)=> b..title = post.title),));
我的ContentsModel
课程内容是:
part 'contents_model.g.dart';
@JsonSerializable(nullable: false)
class ContentsModel{
int id;
String title;
String description;
ContentsModel(this.id, this.postId, this.title, this.description, this.type, this.featuredImages, this.slug, this.lang, this.visit, this.click, this.state, this.createdAt, this.updatedAt, this.categories);
factory ContentsModel.fromJson(Map<String,dynamic> json)=>_$ContentsModelFromJson(json);
Map<String,dynamic> toJson()=>_$ContentsModelToJson(this);
}
答案 0 :(得分:1)
在添加内容之前,您需要初始化列表:
List<PostItem> list = [];
答案 1 :(得分:0)
更改
with open("path/to/logfile.log", "r") as f:
lines = f.readlines()
for error in errors:
for line in lines[-5:]:
if error in line:
return True
return False
到
responses.map((post)=>
list.add(PostItem((b) => b..title = post.title),));
解决了我的问题