如何使用PHP在Graphql模式中添加两个表？

Question

Schema.php

''' $ films = new ObjectType（[                 'name'=>'filmsdetails'，

            'fields' => [
                  'id' => Type::int(),
                  'name' => Type::string(),
                  'uniq_id' => Type::string(),
                  'language' => Type::string(),
                  'rating' => Type::string(),
                  'country' => Type::string(),
                  'genre' => Type::string(),
                  'permalink' => Type::string(),
                  'alias_name' => Type::string(),
                  'story' => Type::string(),
                  'moviestream' => [
                       'type' => Type::listOf($moviestream),

                    ],
            ]
        ]);

$ moviestream = new ObjectType（[                 'name'=>'moviestream_details'

            'fields' => [
                  'id' => Type::string(),
                  'movie_id' => Type::string(),

                  'video_quality' => Type::string(),

                  'full_movie' => Type::string(),
                  'full_movie_url' => Type::string(),
                  'thirdparty_url' => Type::string(),
                  'studio_id' => Type::string(),
                  'sdk_user_id' => Type::string(),
                  'review_flag' => Type::string(),

] ]）;

'''

查询类型

 $queryType = new ObjectType([
                'name' => 'Query',
                'fields' => [
                    'getContentDetails' => [
                        'type' => Type::listOf($films),
                        'args' => [

                            'content_types_id' => Type::string(),
                            'oauth_token' => Type::string(),
                            'permalink' => Type::string(),
                        ],
                        'resolve' => function ($root,$args) {

                            $oauth_token = Oauth::model()->getOauthToken($args["oauth_token"]);                          
                               if($oauth_token['oauth_token'] == $args["oauth_token"]){

                                $user = UserData::model()->getUser($args['permalink'],$oauth_token['studio_id']);
                                $returnArray = [];

                                foreach($user as $key => $data) {
                            //  echo '<script>';
                            // echo 'console.log('. json_encode($data) .')';
                            // echo '</script>';   
//                                    $enddatecondition = Yii::app()->contentCommon->getLiveEndDateCondition('ms');
                                    if ($data["permalink"] == $args["permalink"] && $data["content_types_id"] == $args["content_types_id"]){
                                        $returnArray = $user;
                                }
                                return $user;
                                }
                               }

                        }
                    ],
                ],
            ]);

这里$ films和$ moviestream都是模式类型。在$ films中，我试图访问$ moviestream的数据。

在querytype中，我正在从模型中获取数据。但是它显示了一些错误，即：“期望null为GraphQL类型。”

如何解决？