我有一个表成员,另一个是促销代码。
会员表:
/* 1 */
{
"_id" : ObjectId("5b62e7050b13587e9febb8db"),
"country_id" : "5a093507f1d45633844096ef",
"type" : "Bronze",
"price" : "30",
}
/* 2 */
{
"_id" : ObjectId("5b6961175140b477032291b7"),
"country_id" : "5a093507f1d45633844096ef",
"type" : "Gold",
"price" : "1000",
}....
促销代码表:
{
"_id" : ObjectId("5cfe23fd075be65883f6d921"),
"final_status" : 1,
"membership" : [
ObjectId("5b62e7050b13587e9febb8db"),
ObjectId("5b6961175140b477032291b7"),
ObjectId("5b6961285140b477032291b8"),
ObjectId("5b7567dd5b874856981b53d3"),
ObjectId("5bba1c3794c6761db256edbc")
],
"month" : [
"1",
"3"
]
}
此处,promomcode表具有成员资格ID。我想要带有会员资格的促销代码数据加入query.get带有会员资格详细信息的促销代码数据 请帮助我
答案 0 :(得分:1)
在mongodb中将$ lookup用于左外部联接
db.promocode.aggregate([{
$lookup: {
from: 'membership',
localField: 'membership',
foreignField: '_id',
as: 'memberships'
}
}, {
$project: {
membership: 0
}
}])