Question

我有这个SQL查询

SELECT LEFT(ORIGINALPATH, 34), count(originalpath) as docType1,
(SELECT count(originalpath)
FROM   docType2 
WHERE  ORIGINALPATH LIKE 'D:\era-server\16\ibosdata\00001\%' 
GROUP  BY LEFT(ORIGINALPATH, 34)) AS [dcoType2]
FROM   docType1
WHERE  ORIGINALPATH LIKE 'D:\era-server\16\ibosdata\00001\%' 
GROUP  BY LEFT(ORIGINALPATH, 34) 
ORDER  BY LEFT(ORIGINALPATH, 34);

但是我遇到了以下错误

子查询返回了多个值。当子查询遵循=，！=，<，<=，>，> =，或当子查询用作表达式。

尽管我没有使用这样的运算符。请帮忙。

Answer 1

您可以删除内部分组依据并尝试吗？分组依据可能是在子查询中创建多个行。编辑：添加条件，以确保分组依据与同一分组元素相同。

SELECT LEFT(ORIGINALPATH, 34), count(originalpath) as docType1,
(SELECT count(originalpath)
FROM   docType2 de
WHERE  ORIGINALPATH LIKE 'D:\era-server\16\ibosdata\00001\%' 
and LEFT(de.ORIGINALPATH, 34) = LEFT(d1.ORIGINALPATH, 34)
GROUP  BY LEFT(ORIGINALPATH, 34)) AS [dcoType2]
FROM   docType1 d1
WHERE  ORIGINALPATH LIKE 'D:\era-server\16\ibosdata\00001\%' 
GROUP  BY LEFT(ORIGINALPATH, 34) 
ORDER  BY LEFT(ORIGINALPATH, 34);

子查询返回没有操作符的多行

1 个答案: