如何在Ansible Playbook中使用curl命令

Question

我必须在playook中编写与该curl相同的语法- curl-是“ {{url}}” -H“ Cookie：ROUTEID = 8d1617097a0a51a9e361709ad3f5254b; isBannerTester = 1” | grep -iE'Set-Cookie：|位置'

我必须在playook中编写与该curl相同的语法- curl-是“ {{url}}” -H“ Cookie：ROUTEID = 8d1617097a0a51a9e361709ad3f5254b; isBannerTester = 1” | grep -iE'Set-Cookie：|位置'

- name: "sanity"
  shell: curl -Is "https://{{ENV_DOMAIN}}/applicationNavigator/" -H "Cookie: ROUTEID=8d1617097a0a51a9e361709ad3f5254b; isBannerTester=1"|grep -iE
  args:
     warn: no
  register: res
- debug:
    var: res

错误！加载YAML时的语法错误。   在这种情况下，不允许使用映射值

该错误似乎在“ /mnt/banner/deploy/ansible/sanity_test_update.yml”中：第40行，第84列，但可能 根据确切的语法问题放在文件的其他位置。

违规行似乎是：

    - name: "sanity"
      shell: curl -Is "https://studentconnect.acu.edu.au/BannerAdmin.ws/" -H "Cookie: ROUTEID=8d1617097a0a51a9e361709ad3f5254b; isBannerTester=1"|grep -iE
                                                                                   ^ here
We could be wrong, but this one looks like it might be an issue with
unbalanced quotes. If starting a value with a quote, make sure the
line ends with the same set of quotes. For instance this arbitrary
example:

    foo: "bad" "wolf"

Could be written as:

    foo: '"bad" "wolf"'

Answer 1

尝试建议foo: '"bad" "wolf"'。我认为应该避免引用。

shell: 'curl -Is \"https://{{ENV_DOMAIN}}/applicationNavigator/\"
             -H \"Cookie: ROUTEID=8d1617097a0a51a9e361709ad3f5254b; isBannerTester=1\"|
        grep -iE'

Answer 2

尝试使用uri模块。

- name: curlcommand
  uri:
    url: https://studentconnect.acu.edu.au/BannerAdmin.ws/
    headers:
      Cookie: ROUTEID=8d1617097a0a51a9e361709ad3f5254b
      isBannerTester=1

您甚至可以通过提供状态代码：200 或所需的任何代码来检查特定的状态代码。