Question

有人可以指导我如何在类中重用函数，以便通过导入随机数获得不同的输出吗？

这是我使用python 3.7以Conda为基础的python 3.7代码在VS Code中编写的二十一点游戏。

我正在尝试重用功能player_hand（随机卡），并为player_score（卡值作为整数）获得不同的结果

，然后将这2个得分相加为final_player（最终得分）我非常感谢有关如何应对这一挑战的指导和反馈...

import random

suit = {'Jack': 10, 'Queen': 10, 'King': 10, 'Ace': 11, 'Two': 2, 'Three': 3,
        'Four': 4, 'Five': 5, 'Six': 6, 'Seven': 7, 'Eight': 8, 'Nine': 9}
symb = ['Spade', 'Clubs', 'Heart', 'Diamonds']

player_hand = random.sample(suit.items(), 1) + random.sample(symb, 1)
dealer_hand = random.sample(suit.items(), 1) + random.sample(symb, 1)

player_score = player_hand[0][1]
dealer_score = dealer_hand[0][1]
final_player = player_score + player_score
final_dealer = dealer_score + dealer_score


class Bet:
    def __init__(self, player, bank=0):
        self.bank = bank
        self.player = player

    def __str__(self):
        return f'Player balance: ${self.bank}\n'

    def bet(self):

        self.amount = int(input('Place bet:'))

        if self.bank <= self.amount:
            return 'put more $ '

        else:
            self.bank -= self.amount
            return f'Player balance: ${self.bank}'


class Card:

    def __init__(self, suit, symb):
        self.suit = suit
        self.symb = symb

    def deal(self, player_hand, dealer_hand, dealer_score, player_score):
        while True:
            print('dealer', dealer_hand)
            print('dealer', dealer_score)

            print('player', player_hand)
            print('player', player_score)
            break


class Card2:

    def deal(self, player_hand, dealer_hand, dealer_score, player_score):
            while True:
                print('dealer', dealer_hand)
                print('dealer', dealer_score)

                print('player', player_hand)
                print('player', player_score)
                break

    def total_score(self):
        print(final_dealer)
        print(final_player)

    def winner(self):
        if final_dealer < final_player:
            return 'Player wins!'
        elif final_player < final_dealer:
            return 'dealer wins'


be = Bet('Player', bank=100)

print(be)
print(be.bet())
print('\n')

print(Card.deal('p', player_hand, dealer_hand, dealer_score, player_score))

print('\n')
print(Card2.winner('winner'))

以下输出示例：

Player balance: $100
Place bet:5
Player balance: $95
dealer [('Queen', 10), 'Diamonds']
dealer 10
player [('Seven', 7), 'Heart']
player 7
None
dealer wins

Answer 1

我认为这里的挑战在于理解如何使用类对问题进行建模，特别是如果您是初次接触面向对象编程（OOP）时。

您对于使my_list = '[-0.2226099967956543, 0.2235500067472458, -0.2384900003671646, 0.14377999305725098]' import ast ast.literal_eval(my_list) Out[567]: [-0.2226099967956543, 0.2235500067472458, -0.2384900003671646, 0.14377999305725098]对象（即具有 rank 和 suit 的对象）的构想是一个合理的想法。 但这就是一张卡片应该拥有的全部。所有卡片都具有这两个属性，因此创建类似Card的类几乎没有意义。该卡只是一张纸，不应该知道持有该卡的玩家或庄家，手中的其他卡，玩家的钱等。包括这些无关的数据会导致玩家之间“耦合” ，下注和纸牌彼此之间开始，从而产生“意大利面代码”。

这是从我编写的Card2中绘制Card个对象的快速实现：

Deck

请注意，一旦您编写了各个片段（例如，对牌进行改组和绘制卡片），则主要功能中的代码应该很直观。请让我知道任何代码是否没有道理。

有人可以指导我如何在类中重用函数吗？

1 个答案: