使用Laravel Fram工作提交数据后清除表单输入

时间:2019-06-10 19:46:57

标签: php laravel laravel-5 laravel-5.2

当我验证产品名称并发送消息product name is exist before以查看时,我具有多个数据库连接。

消息出现在视图中,但所有表单输入均被清除。 考虑产品名称不存在时如何解决此问题。验证正确执行,如果发现验证错误,则该错误会正常出现,并且表单输入未清除。 这是我的控制器代码。

public function add(Request $request)
{
    // start add
    if($request->isMethod('post'))
    {

        if(isset($_POST['add']))
        {
            // start validatio array
            $validationarray=$this->validate($request,[

                //'name'  =>'required|max:25|min:1|unique:mysql2.products,name|alpha',
                'name'  =>'required|alpha',
                'price' =>'required|numeric',

            ]);

            // check name is exist
            $query = dBHelper::isExist('mysql2','products','`status`=? AND `deleted` =? AND `name`=?',array(1,1,$validationarray['name']));
            if(!$query) {

                $product=new productModel();

                // start add
                $product->name = $request->input('name');
                $product->save();
                $add = $product->id;
                $poducten = new productEnModel();
                $poducten->id_product = $add;
                $poducten->name = $request->input('name');
                $poducten->price = $request->input('price');
                $poducten->save();
                $dataview['message'] = 'data addes';
            } else {
                $dataview['message'] = 'name is exist before';
            }
        }
    }

    $dataview['pagetitle']="add product geka";
    return view('productss.add',$dataview);
}

这是我的观点

@extends('layout.header')
@section('content')

    @if(isset($message))
        {{$message}}
    @endif

    @if(count($errors)>0)
        <div class="alert alert-danger">
            <ul>
              @foreach($errors->all() as $error)
                  <li>{{$error}}</li>

                  @endforeach

            </ul>

        </div>
        @endif

    <form role="form"  action="add" method="post" enctype="multipart/form-data">
        {{csrf_field()}}
        <div class="box-body">
            <div class="form-group{{$errors->has('name')?'has-error':''}}">
                <label for="exampleInputEmail1">Employee Name</label>
                <input type="text" name="name" value="{{Request::old('name')}}" class="form-control" id="" placeholder="Enter Employee Name">
            </div>

            <div class="form-group">
                <label for="exampleInputEmail1">Email Address</label>
                <input type="text" name="price" value="{{Request::old('price')}}" class="form-control" id="" placeholder="Enter Employee Email Address">
            </div>
        </div>
        <!-- /.box-body -->
        <div class="box-footer">
            <button type="submit" name="add" class="btn btn-primary">Add</button>
        </div>
    </form>

@endsection

这是我的路线

Route::get('/products/add',"produtController@add");
Route::post('/products/add',"produtController@add");

2 个答案:

答案 0 :(得分:0)

您可以手动引发验证异常的第一种方法。 Here,您可以找到解决方法。

第二种方式(我推荐这种方式),您可以生成一个custom validation rule。顺便说一下,您的控制器方法将更干净。

答案 1 :(得分:0)

您可以创建自己的自定义验证功能,如下所示。我想这应该对您有帮助。

https://laravel.com/docs/5.8/validation#custom-validation-rules->使用闭包中找到它

$validationarray = $this->validate($request,
        [
            'name'  => [
                'required',
                'alpha',
                function ($attribute, $value, $fail) { 
                    //$attribute->input name, $value for that value.
                    //or your own way to collect data. then check.
                    //make your own condition.
                    if(true !=dBHelper::isExist('mysql2','products','`status`=? AND `deleted` =? AND `name`=?',array(1,1,$value))) {                        
                           $fail($attribute.' is failed custom rule. There have these named product.');
                    }
                },          
            ],
            'price' => [
                'required',
                'numeric',
            ]        
        ]);