Question

我想通过搜索查询显示主表中的全部数据，并按名称搜索城市和州，并在主表中输入城市和州ID，而不是名称。

核心php API中的phpmyadmin mysql数据库。


if(!empty($state_id))
{
$condition .="sangh_directory.state like '$state_id%'";

}   
if(!empty($city_id))
{
$condition .="and sangh_directory.city like '$city_id%'";
}
if(!empty($searchsangh))
{
$condition .="sangh_directory.sangh_name like '$searchsangh%'";
}
$DirectoryDetailsQuery=$con->select_query("sangh_directory","*","inner join city on city.city_id=sangh_directory.city inner join country ON country.country_id=sangh_directory.country inner join state ON state.state_id=sangh_directory.state where $condition");

选择查询表名称为：sangh_directory时出现错误您的SQL语法有错误；检查与您的MySQL服务器版本相对应的手册以获取正确的语法，以在第1行的'and sangh_directory.city之类的'Ahme％'附近使用

Answer 1

尝试一下：

$condition = "1=1";

if(!empty($state_id)) {
    $condition .=" and sangh_directory.state like '$state_id%'";
}   
if(!empty($city_id)) {
    $condition .=" and sangh_directory.city like '$city_id%'";
}
if(!empty($searchsangh)) {
    $condition .=" and sangh_directory.sangh_name like '$searchsangh%'";
}
$DirectoryDetailsQuery=$con->select_query("sangh_directory","*","inner join city on city.city_id=sangh_directory.city inner join country ON country.country_id=sangh_directory.country inner join state ON state.state_id=sangh_directory.state where $condition");

很抱歉，如果这在语法上不正确，希望您能理解要点。

如果您要建立一个公开的网站，请观看this video或阅读有关SQL注入的其他内容，如@Dharman所建议的那样。

并阅读有关确保网站安全的其他主题。

我想按名称搜索城市和州，并想在该表中搜索插入城市和州ID的

1 个答案: