当显示客户ID时,我收到错误消息。我也尝试更改属性“ id”的名称,但是使用新名称来出现相同的错误。
HTTP状态500-内部服务器错误
类型例外报告 消息内部服务器错误 说明:服务器遇到内部错误,无法满足该请求。
例外 org.apache.jasper.JasperException:javax.el.PropertyNotFoundException:类'de.java2enterprise.onlineshop.model.Customer'没有属性'id'。
根本原因 javax.el.PropertyNotFoundException:类'de.java2enterprise.onlineshop.model.Customer'没有属性'id'。
注释,该异常的完整堆栈跟踪及其根本原因可在GlassFish Server Open Source Edition 5.1.0日志中找到。
HTML:
<%@ include file="header.jspf" %>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Onlineshop</title>
</head>
<body>
<c:forEach var="customer" items="${customers}">
<article>
<p>${customer.id}</p>
<p>${customer.email}</p>
<p>test</p>
</article>
</c:forEach>
<%@ include file="footer.jspf" %>
Java类
软件包de.java2enterprise.onlineshop.model;
导入java.io.Serializable;
客户公开类实现了可序列化{ 私有静态最终长serialVersionUID = 1L;
private Long id;
private String email;
private String password;
public Customer() {}
public Customer(String email, String password) {
this.email = email;
this.password = password;
}
public Long getID() {
return id;
}
public void setID(Long id) {
this.id = id;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String toString() {
return
"[" +
getID() + ", " +
getEmail() + ", " +
getPassword() +
"]";
}
}
控制器
@WebServlet("/userShow")
公共类UserServlet扩展了HttpServlet { 私有静态最终长serialVersionUID = 1L;
@Resource
private DataSource ds;
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doPost(request, response);
}
public void doPost( HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
try {
List<Customer> customers = find();
if (customers != null) {
HttpSession session = request.getSession();
session.setAttribute("customers", customers);
}
} catch (Exception e) {
throw new ServletException(e.getMessage());
}
RequestDispatcher dispatcher = request.getRequestDispatcher("search.jsp");
dispatcher.forward(request, response);
}
public List<Customer> find() throws Exception {
List<Customer> customers = new ArrayList<Customer>();
try (final Connection con = ds.getConnection();
final PreparedStatement stmt = con
.prepareStatement(
"SELECT " +
"id, " +
"email, " +
"password " +
"FROM onlineshop.customer ")) {
ResultSet rs = stmt.executeQuery();
while (rs.next()) {
Customer customer = new Customer();
Long id = Long.valueOf(rs.getLong("id"));
customer.setID(id);
String email = rs.getString("email");
customer.setEmail(email);
String password = rs.getString("password");
customer.setPassword(password);
customers.add(customer);
}
}
return customers;
}
}
答案 0 :(得分:0)
您的Customer
类需要遵循Java Bean的命名约定:
它是getId/setId
而不是getID/setID
。