Question

我有此数据：

ID  PERSNR  YEARNR  MONTHNR DAYNR   ABSTIME ABSID   ABSCALC TypeLine
---------------------------------------------------------------------
 1  26      2018    12      3       480     3       11      0
 2  26      2018    12      3       480     3       11      1
 5  26      2018    10      1        60     1       31      0
 8  26      2018    10      3        60     1       31      0
13  69      2018    12      3       480     3       11      0
14  69      2018    12      3       480     3       11      1
19  69      2018     9      3        60     3       31      1
22  69      2018     9      3        60     3       31      0
23  69      2018     9      3       420    21       11      0
26  69      2018     9      6       120    21       31      1
29  69      2018     9     10       120    21       31      1
32  69      2018     9      4       480    21       11      1

我需要确定以下情况：

同时具有TypeLine 0和1的行结果ID：1和2； 13和14、19和22
仅具有TypeLine的行0 结果ID：5； 8; 23
仅具有TypeLine的行1 结果ID：26、29、32

我不确定要创建这3个脚本，但是找不到解决方案。

你能帮我吗？

Answer 1

这是您想要的吗？

select (case when cnt_type_0 > 0 and cnt_type_1 > 0
             then 'Condition 1'
             when cnt_type_1 = 0
             then 'Condition 2'
             when cnt_type_0 = 0
             then 'Condition 3'
        end) as condition,
       t.*
from (select t.*,
             count(*) over (partition by ID, PERSNR, YEARNR, MONTHNR, DAYNR, ABSTIME, ABSID, ABSCALC) as cnt,
             sum(case when TypeLine = 0 then 1 else 0 end) over (partition by ID, PERSNR, YEARNR, MONTHNR, DAYNR, ABSTIME, ABSID, ABSCALC) as cnt_type_0,             
             sum(case when TypeLine = 1 then 1 else 0 end) over (partition by ID, PERSNR, YEARNR, MONTHNR, DAYNR, ABSTIME, ABSID, ABSCALC) as cnt_type_1
       from t
      ) t
where cnt >= 2;

您可以将条件添加到WHERE子句中，以获取仅一种类型的行。

Answer 2

尝试这样的事情：

SELECT DISTINCT ID, 
PERSNR, 
YEARNR, 
MONTHNR, 
DAYNR, 
ABSTIME, 
ABSID, 
ABSCALC, 
iif(count(TypeLine) >= 2, 'duplicate', iif(min(TypeLine) = 1, '1', '0')) as status
FROM table
GROUP BY ID, PERSNR, YEARNR, MONTHNR, DAYNR, ABSTIME, ABSID, ABSCALC

Answer 3

假设源数据正确，则可以运行以下3个查询。＃1当前回答正确，但是＃2和＃3在当前版本的问题中具有不同的DAYNUM，因此您不会使用这些示例值返回任何内容...

--1
SELECT T1.ID AS [T1_ID], T2.ID AS [T2_ID]
  FROM [tablename] T1 INNER JOIN [tablename] T2 ON T1.PERSNR = T2.PERSNR 
  AND T1.YEARNR = T2.YEARNR AND T1.MONTHNR = T2.MONTHNR
  AND T1.DAYNR = T2.DAYNR AND T1.ABSTIME = T2.ABSTIME
  AND T1.ABSID = T2.ABSID AND T1.ABSCALT = T2.ABSCALT
  AND (T1.TypeLine = 0 AND T2.TypeLine = 1
       OR
       T1.TypeLine = 1 AND T2.TypeLine = 0
      )
  AND T1.ID < T2.ID

--2
SELECT T1.ID AS [T1_ID], T2.ID AS [T2_ID]
  FROM [tablename] T1 INNER JOIN [tablename] T2 ON T1.PERSNR = T2.PERSNR 
  AND T1.YEARNR = T2.YEARNR AND T1.MONTHNR = T2.MONTHNR
  AND T1.DAYNR = T2.DAYNR AND T1.ABSTIME = T2.ABSTIME
  AND T1.ABSID = T2.ABSID AND T1.ABSCALT = T2.ABSCALT
  AND T1.TypeLine = 0 AND T2.TypeLine = 0
  AND T1.ID < T2.ID

--3 
SELECT T1.ID AS [T1_ID], T2.ID AS [T2_ID]
  FROM [tablename] T1 INNER JOIN [tablename] T2 ON T1.PERSNR = T2.PERSNR 
  AND T1.YEARNR = T2.YEARNR AND T1.MONTHNR = T2.MONTHNR
  AND T1.DAYNR = T2.DAYNR AND T1.ABSTIME = T2.ABSTIME
  AND T1.ABSID = T2.ABSID AND T1.ABSCALT = T2.ABSCALT
  AND T1.TypeLine = 1 AND T2.TypeLine = 1       
  AND T1.ID < T2.ID

查找具有重复列但由指定值的一列隔开的行

3 个答案: