Spring Security-使用基本身份验证失败的登录尝试

时间:2019-06-10 11:12:16

标签: spring spring-security basic-authentication

我们的应用程序的安全性是通过使用用户详细信息服务的基本身份验证配置构建的。现在,我们要求在3次失败的登录尝试后禁用用户。

我一直在尝试在Internet上搜索有关实现方法的一些想法,但是我仅找到引用表单登录的示例。

是否有可用于基本身份验证的登录失败处理程序。我看过用CREATE PROCEDURE getFavChefsDetailsAndExperience(IN usr_id int) RETURNS ? BEGIN DECLARE n INT DEFAULT 0; DECLARE i INT DEFAULT 0; DROP TEMPORARY TABLE IF EXISTS myFavChefsIds; CREATE TEMPORARY TABLE IF NOT EXISTS myFavChefsIds AS (SELECT fk_usr_chef_id, @curRow := @curRow + 1 AS row_no FROM followers JOIN (SELECT @curRow := 0) r WHERE fk_usr_id = usr_id); DROP TEMPORARY TABLE IF EXISTS myFavChefsDetails; CREATE TEMPORARY TABLE IF NOT EXISTS myFavChefsDetails AS (SELECT * FROM ( SELECT * FROM users u INNER JOIN zipcodes z ON u.fk_zip_id = z.zip_id GROUP BY usr_firstname, usr_lastname) AS D LEFT JOIN ( SELECT fk_usr_chef_id, count(DISTINCT fk_mls_id) as mls_cooked, count(*) as ord_finished, sum(rat_weight)/count(rat_weight),1) as avg_rating FROM ratings r RIGHT JOIN orders o ON o.fk_rat_id = r.rat_id LEFT JOIN meals m ON o.fk_mls_id = m.mls_id WHERE mls_date<now() AND o.fk_usr_cons_id IS NOT null) AS E ON D.usr_id = E.fk_usr_chef_id); IF NOT EXISTS (SELECT * FROM myFavChefsIds) THEN SET i=0; SELECT COUNT(*) AS n FROM myFavChefsIds; WHILE i<n DO SET i = i + 1; // IS IT POSSIBLE TO DO SOMETHING LIKE THIS? x = SELECT ... FROM ... WHERE row_no = i IF (i != n) THEN x += UNION END WHILE; //RETURN UNION STATEMENT END IF; END; 配置exceptionHandling(),但它甚至没有被触发。

0 个答案:

没有答案
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