Question

我正在创建一个程序，该程序需要两个输入，当前权重和目标权重。根据输入的不同，它显示不同的输出，例如电流：87和目标64，每周损失1.38，我希望它计算总和直到达到当前<=目标的次数。

我尝试进行循环，但是我没有足够的技能来完全理解循环的工作原理。

//Declare basic variables, prompt asks for input from user.
var current = prompt("Please enter your current weight");
var target = prompt("Please enter your target weight");
var weeks = 0; 
var loss = (current - target);
// If 0 is entered by user then the input text will display
if (current <= 0){
    document.write("Invalid input, please enter greater than 0 kg"); // Displays answer
}
// If 0 is entered by user then the input text will display
else if (target <= 0){
    document.write("Invalid input, please enter greater than 0 kg"); // Displays answer
}
else if (target >= current){
    document.write("Invalid input, please enter greater than 0 kg"); // Displays answer
}
// Calculate the weeks it takes to lose weight
else if (current > target){
    loss = (target - current);
    weeks = loss / 1.38;
    document.write(weeks.toFixed(0)); // Displays answer
}

我希望电流= 87和目标= 64的预期输出为“ 17周”。

Answer 1

首先，您需要替换该行以避免产生负面结果：

 this.medicineSupply = this.formBuilder.group({
 is_partial:[''],
 durationSupply:[''],
 durationSupplyTypeId: [''],
 resultStored:this.formBuilder.array([
  this.formBuilder.group({
      is_partial_id:[''],
      durationSupplyID_id:[''],
      durationSupplyTypeId_id:['']
    })
  ]),
})

具有：

loss = (target - current);

第二，在输出中添加“周”：

loss = (current - target);

document.write(weeks.toFixed(0) + ' weeks');

Answer 2

我不知道您的代码的一般正确性，但是如果我只是对其进行修改以一遍又一遍地重新运行，直到获得有效的结果，然后算上，我会这样做：

var finished = false;
var count = 0;


while (!finished) {
    count++;
    //Declare basic variables, prompt asks for input from user.
    var current = prompt("Please enter your current weight");
    var target = prompt("Please enter your target weight");
    var weeks = 0; 
    var loss = (current - target);

    // If 0 is entered by user then the input text will display
    if (current <= 0){
       document.write("Invalid input, please enter greater than 0 kg"); // Displays answer
    }
    // If 0 is entered by user then the input text will display
    else if (target <= 0){
       document.write("Invalid input, please enter greater than 0 kg"); // Displays answer
    }
    else if (target >= current){
       document.write("Invalid input, please enter greater than 0 kg"); // Displays answer
    }
    // Calculate the weeks it takes to lose weight
    else if (current > target){
        finished = true;
        loss = (target - current);
        weeks = loss / 1.38;
        document.write(weeks.toFixed(0)); // Displays answer
    }
}

使用finished变量来跟踪是否应该再次运行循环，并且count变量在每次循环时都会递增。得到满意的结果时，将finished设置为true。

Answer 3

function looseWeightEstimator() {
    let weeksToAchieve, currentWeight, targetWeight;
    weeksToAchieve = 0;
    currentWeight = prompt("Please enter your current weight");
    targetWeight = prompt("Please enter your target weight");



    for (let i = 0; currentWeight > targetWeight; i++) {
        weeksToAchieve = weeksToAchieve + 1
        currentWeight = currentWeight - 1.38;
    }
    alert(`It will take ${weeksToAchieve} weeks to achieve your target weight`);


}

looseWeightEstimator()

我如何计算计算已经运行了多少次

3 个答案: