Question

我有一个端点在最近5分钟中被击中100次。端点响应 2xx 90次， 5xx 10次。因此，我们可以将错误率称为 100/10 = 10％。

//To store even and odd element in 2 diifferent array Aand print it//
import java.util.*;
class main11
{
    public static void main(String args[])
    {
        Scanner sc=new Scanner(System.in);
        System.out.println("Enter the range");
        int no=sc.nextInt();
        int a[]=new int[no];
        int i,j=0,k=0;
        System.out.println("Enter the elements");
        for(i=0;i<no;i++)
        {
            a[i]=sc.nextInt();
        }
        int even[]=new int[no];
        int odd[]=new int[no];
        System.out.println("Even nos are");
        for(i=0;i<no;i++)
        {
            if(a[i]%2==0)
            { 
                even[i]=a[i];//to store element in even array//
                System.out.println(even[i]+" ");

            }

        }
        System.out.println("The odd nos are");
        for(i=0;i<no;i++)
        {
            if(a[i]%2!=0)
            {  
                odd[i]=a[i];//to store element in odd array//

                System.out.println(odd[i]+" ");

            }

        }




        }

    }

我的第一个查询是如何检查我的错误率是否为10％或更大最近5分钟内的比重是10％？

现在我有一个全新的应用程序，该应用程序获取下面描述的请求数（每个请求均从0开始）。

city_list = []

def loopJson():

    arrs = ['Đường Lê Quang Định', 'Phường 11', 'Bình Thạnh', 'Hồ Chí Minh']

    with open('reform_address.json','r') as jfile:

        j_data = json.load(jfile)

    for x in j_data:
        new_cities = {}
        city_name = x
        city_code = (j_data[x]['cityCode'])

        for d_name in j_data[x]['districts']:
            district_name = d_name
            district_code = (j_data[x]['districts'][d_name]['districtCode'])

        for w_name,w_code in j_data[x]['districts'][d_name]['wards'].items():
            if w_name in arrs:
                ward_name = w_name
                ward_code = w_code

        for s_name,s_code in j_data[x]['districts'][d_name]['streets'].items():
            if s_name in arrs:
                street_name = s_name
                street_code = s_code

        new_cities.update({city_name: city_code, district_name: district_code, ward_name: ward_code, street_name: street_code})
        city_list.append(new_cities)

loopJson()

print(city_list)

我的第二个查询是如何根据端点或方法还是两者？

计算X分钟普罗米修斯之间端点的错误率

0 个答案: