Question

我现在遇到的问题是，它不会根据用户输入打印出输入。示例：

在我要向日历中添加日程表的日期插入之后，我输入的任务是“ C ++”，但是程序中什么都没有中断。我希望它可以打印“ C ++”，我认为应该在此部分出现问题：

for (;;) {
  cout << "You task: " << endl;
  string sunday;
  if (!getline(cin,sunday) || sunday.empty())break;
  sunday_task.push_back(sunday);
  for (int i = 0; i<sunday_task.size(); i++){ // This part does not work
      cout << sunday_task[i] << endl; // This part does not work
    }

我尝试了很多答案，但似乎没有用。

#include <iostream>
#include <windows.h>
#include <vector>
#include <time.h>
#include <string>
#include <algorithm>
#include <stack>


using namespace std;



string login() {
  start:
  cout << "Please login to access your account" << endl;
  cout << "Please enter your username or email: " ;
  string username;
  getline (cin,username);
 if (username == "duxton"){
   cout << "Please enter your password:";
   string password;
   getline (cin, password);
   if (password == "password") {
     cout << "You have successfully login" << endl;
     char choice;
     cout << "\n\nChoose one of the choice below:\n"
          << "a. Add a schedule to your calender\n"
          << "b. View your schedule for the month\n"
          << "c. Exit\n\n";


      //Get the choice
     cout << "Insert Option:";
     cin  >> choice;



  // potential to be use in struct
  vector <string> sunday_task ;


  string days;


  switch (choice)
  {
  case 'a': cout <<"Sunday   Monday  Tuesday  Wednesday  Thursday  Friday  Saturday" << endl;
  cout << "Which day would you like to insert task to? " << endl;
  cout << "Insert day : " ;
  cin >> days;
  if (days == "Sunday" or "sunday")
  {
    for (;;) {
      cout << "You task: " << endl;
      string sunday;
      if (!getline(cin,sunday) || sunday.empty())break;
      sunday_task.push_back(sunday);
      for (int i = 0; i<sunday_task.size(); i++){
          cout << sunday_task[i] << endl;
        }

    }


  }
            break;
       case 'b':    cout << "View calender" << endl;


             break;
       case 'c':    break;


       default:
         cout << "Input Error!";

       }


     }
     else {
       cout << "Login failed" << endl; goto start;
     }

      }
   else { cout << "Login failed" << endl; goto start;}

   cin.get();


 }

 int main(){
     login();

     return 0;
 }

我的输出是：

Please login to access your account
Please enter your username or email: duxton
Please enter your password: password
You have successfully login 

Choose one of the choice below:
a. Add a schedule to your calender
b. View your schedule for the month
c. Exit

Insert Option:a
Sunday   Monday  Tuesday  Wednesday  Thursday  Friday  Saturday
Which day would you like to insert task to?
Insert day : sunday
You task: c++

^^在这部分之后，我希望它能打印出“ C ++”

对不起，因为我是StackOverflow的新手，我希望我已经清楚地说明了这一点，并提供了足够的信息。

Answer 1

不相关的问题：string login()就像我在相邻评论中提到的那样，如果您承诺一个字符串，则必须返回一个，否则会发生不好的情况。或将功能更改为void。始终在启用警告的情况下进行编译，请尝试对其进行修复。

您的问题是 cin >> string_variable和cin >> char_variable在cin中留下未处理的换行符，因此，下次执行getline时，将得到一个空字符串。在string temp; getline(cin, temp);之后和cin >> choice;之后放置cin >> days;之类的东西，以吃掉多余的换行符。

它不会打印出基于用户输入c ++输入的任务

1 个答案: