我正在尝试使用类似于Rot13的算法在PHP中编码字符串,然后在JavaScript中解码该字符串并进行搜索和替换。它可以与ASCII字符一起正常工作,但不适用于Unicode。
我把附带的代码弄乱了,但是无法正常工作。
<?php
function strRot($str, $n) {
$len = mb_strlen($str);
$min = 0;
$max = 99999999;
$final = '';
for ($i = 0; $i < $len; $i++) {
$current = mb_ord($str[$i]);
$val = $current+$n;
if ($val >= $max) {
$val = $val - $max;
}
if ($val <= $min) {
$val = $val + $min;
}
$final .= mb_chr($val);
}
return $final;
}
?><!doctype html>
<html lang="en">
<head>
<!-- Required meta tags -->
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<!-- Bootstrap CSS -->
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.2.1/css/bootstrap.min.css" integrity="sha384-GJzZqFGwb1QTTN6wy59ffF1BuGJpLSa9DkKMp0DgiMDm4iYMj70gZWKYbI706tWS" crossorigin="anonymous">
<title>Hello, world!</title>
</head>
<body>
<h1>Hello, world!</h1>
<h2>Ü and ?. 棕色的狐狸跳了起来.</h2>
<p>The Hello, world! expression will be replaced.</p>
<p>Ü and ?. 棕色的狐狸跳了起来. Should be replaced too.</p>
<!-- Optional JavaScript -->
<!-- jQuery first, then Popper.js, then Bootstrap JS -->
<script src="https://code.jquery.com/jquery-3.3.1.slim.min.js" integrity="sha384-q8i/X+965DzO0rT7abK41JStQIAqVgRVzpbzo5smXKp4YfRvH+8abtTE1Pi6jizo" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.6/umd/popper.min.js" integrity="sha384-wHAiFfRlMFy6i5SRaxvfOCifBUQy1xHdJ/yoi7FRNXMRBu5WHdZYu1hA6ZOblgut" crossorigin="anonymous"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.2.1/js/bootstrap.min.js" integrity="sha384-B0UglyR+jN6CkvvICOB2joaf5I4l3gm9GU6Hc1og6Ls7i6U/mkkaduKaBhlAXv9k" crossorigin="anonymous"></script>
<script id="scriptId" type="text/javascript">
var data = [
["Hello, world!", "<?php echo base64_encode(strRot('I got replaced.', 1000)); ?>"],
["Ü and ?. 棕色的狐狸跳了起来.", "<?php echo base64_encode(strRot('? before Ü and 棕色的.', 1000)); ?>"]
];
function b64DecodeUnicode(str) {
// Going backwards: from bytestream, to percent-encoding, to original string.
return decodeURIComponent(atob(str).split('').map(function(c) {
return '%' + ('00' + c.charCodeAt(0).toString(16)).slice(-2);
}).join(''));
}
function strRot(str, n)
{
var min = 0;
var max = 99999999;
var final = '';
for (var i in str) {
var current = str.charCodeAt(i);
var val = current+n;
if (val >= max) {
val = val - max;
}
if (val <= min) {
val = val + min;
}
final += String.fromCharCode(val);
}
return final;
}
function replace() {
for (index in data) {
//var regex = new RegExp(data[index][0], "ug");
jQuery("html *:not(script[id=scriptId])").children().each(function () {
jQuery(this).html(jQuery(this).html().replace(
data[index][0],
strRot(b64DecodeUnicode(data[index][1]), -1000)
));
});
}
}
replace();
</script>
</body>
</html>
一旦JS运行,就应该用解码后的数据[index] [1]替换data [index] [0]。
答案 0 :(得分:0)
(我没有足够的声誉来发表评论,所以诉诸于使用答案...)
不确定是否会有所不同,但是在HTML“ h2”标头中,您的Unicode表达式为...
Ü an ?. 棕色的狐狸跳了起来.
...在data []中,是...
Ü and ?. 棕色的狐狸跳了起来.
假定“ an”和“ and”应该相同?
答案 1 :(得分:0)
我找到了一个解决方案:
var data = [
["Hello, world!", "<?php echo base64_encode(strRot(rawurlencode('I got replaced.'), 1000)); ?>"],
["Ü and ?. 棕色的狐狸跳了起来.", "<?php echo base64_encode(strRot(rawurlencode('? before Ü and 棕色的.'), 1000)); ?>"]
];
// Then, in replace():
decodeURIComponent(strRot(b64DecodeUnicode(data[index][1]), -1000))
之所以有用,是因为它在旋转所有Unicode字符之前会将其转义。 唯一的问题是,由于转义,字符串大小增加了一些开销。