Question

我不是很擅长为JOSN解码构建结构，因此希望能有所帮助。我有以下JSON

{
    "computer": {
        "location": {
            "username": "john.smith",
            "realname": "john smith",
            "real_name": "johnsmith",
            "email_address": "johnsmith@company.com",
            "position": "somePosition",
            "phone": "123-456-7890",
            "phone_number": "123-456-7890",
            "department": "",
            "building": "",
            "room": "someRoom01"
        }
    }
}

我创建了以下结构来保存它：

struct ComputerRecord: Codable {
        public let locationRecord: Location
    }

    struct Location: Codable {
        public let record: Record
    }

    struct Record: Codable {
        public let username: String
        public let realname: String
        public let real_name: String
        public let email_address: String
        public let position: String
        public let phone: String
        public let phone_number: String
        public let department: String
        public let building: String
        public let room: String
    }

当我尝试对其进行解码并像这样使用它（带有完成处理程序的较大功能的一部分）时：

do {
    let decoder = JSONDecoder()
    let computer = try decoder.decode(jssComputerRecord.self, from: data)

    if  computer.locationRecord.record.username == nameToCheck {
        usernameSet(true, response, error)
    } else {
          print("In the else")
          usernameSet(false, response, error)
      }
} catch {
      print(error)
      usernameSet(false, response, error)
  }

我抓住了这个错误：

keyNotFound(CodingKeys(stringValue: "locationRecord", intValue: nil), Swift.DecodingError.Context(codingPath: [], debugDescription: "No value associated with key CodingKeys(stringValue: \"locationRecord\", intValue: nil) (\"locationRecord\").", underlyingError: nil))

我认为这是我构造Structs进行解码的方式时出现的错误，就像打印数据的字符串版本一样，我得到了上面显示的JSON。

注意：我已将记录匿名化，但保留了完整的结构。

任何对此的帮助都会很棒。

谢谢

Ludeth（Ed）

Answer 1

最重要的规则是：

结构成员的名称必须与JSON密钥匹配，除非您使用CodingKeys

映射密钥

为了符合命名约定，我添加了 snake_case 转换

struct ComputerRecord: Codable {
    public let computer: Computer
}

struct Computer: Codable {
    public let location: Record
}

struct Record: Codable {
    public let username: String
    public let realname: String
    public let realName: String
    public let emailAddress: String
    public let position: String
    public let phone: String
    public let phoneNumber: String
    public let department: String
    public let building: String
    public let room: String
}

do {
    let decoder = JSONDecoder()
    decoder.keyDecodingStrategy = .convertFromSnakeCase
    let result = try decoder.decode(ComputerRecord.self, from: data)

    if result.computer.location.username == nameToCheck {
        usernameSet(true, response, error)
    } else {
        print("In the else")
        usernameSet(false, response, error)
    }
} catch {
      print(error)
      usernameSet(false, response, error)
  }

从API解码JSON-Swift 5

1 个答案: