Question

我正在尝试将一些C ++代码转换为MATLAB并遇到问题。有人请从下面解释一行代码。

  int *image      = (int *) malloc(size*sizeof(int)) ;

  bool diff = true;
  while (diff)
  {
     diff = false;
    for (unsigned int itt = 0; itt < size; itt++)
    {
      diff = diff || (image[itt] != image[image[itt]]);
      image[itt] = image[image[itt]];
    }
  }

有人可以从

解释

  diff = diff || (image[itt] != image[image[itt]]);
  image[itt] = image[image[itt]];

这部分

image[image[itt]]

我不明白这是如何工作的MATLAB

Image = zeros(100,100);

ImageSize = (Image);
diff = true;

while(diff)
    diff = false;
    for x=1:ImageSize(1) % Height
        for y=1:ImageSize(2) % Width
        diff = diff || (image(x,y) ~= ????);
        image(x,y) = ????;
        end
    end
end

感谢任何能帮助我理解这一点的人。

Answer 1

首先，ImageSize = (Image);不正确。这只会将Image分配给ImageSize。请改用ImageSize = size(Image);。

其次，您在Matlab代码中使用双索引，而C ++代码使用单个索引。

while(diff)
    diff = false;
    for n=1:numel(Image) %# Total pixels in the image
        diff = diff || (Image(n) ~= Image(Image(n)));
        Image(n) = Image(Image(n));
    end
end

您可能需要转置矩阵，因为我不确定C ++代码是按行方式还是按行方式操作。另外，因为你正在将矩阵初始化为全零（zeros(100,100);），所以你将得到全部为零的结果。尝试将其初始化为实际图像或至少随机整数。

干杯！

将C ++转换为MATLAB

1 个答案: