任何人都能说出这是什么类型的转换

Question

我将输入作为左侧11位数字，输出应该在那之前，或者任何人都可以告诉我如何获得那些输出byu将这些输入作为字节数组

Answer 1

这远非优化，但这应该有效

int code = Convert.ToInt32("0x" + "82", 16);  //this is your first char
code = code >= 0x20 && code < 0x7f ? code : 0x2E;
byte b = Convert.ToByte(code);  
string txt = System.Text.Encoding.UTF8.GetString(new byte[] { b });

Answer 2

如果你已经将输入作为字节数组，那么这应该给你字符串;

string result = Encoding.ASCII.GetString(input); // where "input" is your byte[]

Answer 3

编码似乎为ASCII，但由于某种原因，某些字符的高位设置。您可以清除该位并使用Encoding.ASCII从字节数组构建字符串：

string result = Encoding.ASCII.GetString(
    yourByteArray.Select(b => (byte) (b & 0x7F)).ToArray());

编辑：如果你不能使用LINQ，你可以这样做：

for (int i = 0; i < yourByteArray.Length; ++i) {
    yourByteArray[i] &= 0x7F;
}

string result = Encoding.ASCII.GetString(yourByteArray);

Answer 4

Example of first line

@changed支持点     string [] line =“82 44 b4 2e 39 39 39 39 39 35”.Split（''）;

byte[] bytes = new byte[line.Length];

for (int i = 0; i < line.Length; i++) {
  int candidate = Convert.ToInt32(line[i], 16);
  if (!(!(candidate < 0x20 || candidate > 127)))
    candidate = 46; //.
  bytes[i] = Convert.ToByte(candidate);
}

string s =  System.Text.Encoding.ASCII.GetString(bytes);

Answer 5

为了帮助您入门：

// Convert the number expressed in base-16 to an integer.
int value = Convert.ToInt32(hex, 16);

这取自MSDN

Answer 6

byte[] bytes=new byte[]{0xf3,0x28,0x48,0x78,0x98};
var output=string.Concat( 
    bytes.Select(b => (char) (b >= 0x20 && b<0x7f ? b :(byte)'.') ).ToArray()
);