Question

我想知道我们是否可以通过提供键值对来从json中获取项目。

例如我有一个像下面的json对象

[
{id: "864", text: "[145-028] ", name: "145028", type: null, description: ""},
{id: "593", text: "[111-111] ", name: "111111", type: null, description: ""},
{id: "616", text: "[330-00D] ", name: "33000D", type: null, description: ""},
{id: "595", text: "[124-964] ", name: "124964", type: null, description: ""},
{id: "597", text: "[476-978] ", name: "476978", type: null, description: ""},
{id: "131", text: "[142-222] ", name: "142222", type: null, description: ""},
{id: "132", text: "[149-603] ", name: "149603", type: null, description: ""},
{id: "603", text: "[778-498] ", name: "778498", type: null, description: ""}
]

如何获取ID为864的单个商品，以便获取特定商品的名称，类型和说明。

任何帮助将不胜感激

Answer 1

您可以使用filter。它将返回另一个数组。使用index获取对象并从中获取名称

let data = [{
    id: "864",
    text: "[145-028] ",
    name: "145028",
    type: null,
    description: ""
  },
  {
    id: "593",
    text: "[111-111] ",
    name: "111111",
    type: null,
    description: ""
  },
  {
    id: "616",
    text: "[330-00D] ",
    name: "33000D",
    type: null,
    description: ""
  },
  {
    id: "595",
    text: "[124-964] ",
    name: "124964",
    type: null,
    description: ""
  },
  {
    id: "597",
    text: "[476-978] ",
    name: "476978",
    type: null,
    description: ""
  },
  {
    id: "131",
    text: "[142-222] ",
    name: "142222",
    type: null,
    description: ""
  },
  {
    id: "132",
    text: "[149-603] ",
    name: "149603",
    type: null,
    description: ""
  },
  {
    id: "603",
    text: "[778-498] ",
    name: "778498",
    type: null,
    description: ""

  }
];

function getval(id) {

  let obj = data.filter(item => item.id === id);
  return obj[0].name;
}

console.log(getval('864'))

或者，您也可以使用find。与filter不同，它将返回id匹配的第一个对象。

let data = [{
    id: "864",
    text: "[145-028] ",
    name: "145028",
    type: null,
    description: ""
  },
  {
    id: "593",
    text: "[111-111] ",
    name: "111111",
    type: null,
    description: ""
  },
  {
    id: "616",
    text: "[330-00D] ",
    name: "33000D",
    type: null,
    description: ""
  },
  {
    id: "595",
    text: "[124-964] ",
    name: "124964",
    type: null,
    description: ""
  },
  {
    id: "597",
    text: "[476-978] ",
    name: "476978",
    type: null,
    description: ""
  },
  {
    id: "131",
    text: "[142-222] ",
    name: "142222",
    type: null,
    description: ""
  },
  {
    id: "132",
    text: "[149-603] ",
    name: "149603",
    type: null,
    description: ""
  },
  {
    id: "603",
    text: "[778-498] ",
    name: "778498",
    type: null,
    description: ""

  }
];

function getvalUsingFind(id) {

  let obj = data.find(item => item.id === id);
  return obj;
}

console.log(getvalUsingFind('864').name)

Answer 2

我建议：

const MyData = [{ 0: {id: "864", text: "[145-028] ", name: "145028", type: null, description: ""}
                , 1: {id: "593", text: "[111-111] ", name: "111111", type: null, description: ""} 
                , 2: {id: "616", text: "[330-00D] ", name: "33000D", type: null, description: ""} 
                , 3: {id: "595", text: "[124-964] ", name: "124964", type: null, description: ""} 
                , 4: {id: "597", text: "[476-978] ", name: "476978", type: null, description: ""} 
                , 5: {id: "131", text: "[142-222] ", name: "142222", type: null, description: ""} 
                , 6: {id: "132", text: "[149-603] ", name: "149603", type: null, description: ""} 
                , 7: {id: "603", text: "[778-498] ", name: "778498", type: null, description: ""} 
                }];

function MyDataGetVal(x_ID) {
  return Object.values(MyData[0]).find(E=>E.id===x_ID )|| null;
}


let E_864 = MyDataGetVal('864')
  , E_132 = MyDataGetVal('132')
  , E_XXX = MyDataGetVal('XXX')
;

console.log ('E_864 = ',  JSON.stringify(E_864))

console.log ('E_132 = ',  JSON.stringify(E_132))

console.log ('E_XXX = ',  JSON.stringify(E_XXX))

使用key：value从json对象获取项目

2 个答案: