Question

我正在尝试使用SUM()在股票表中的GROUP_CONCAT()列，但似乎无法获得我想要的输出。

MySQL表：

CREATE TABLE 'suppliers' (
 'id' int(11) NOT NULL AUTO_INCREMENT,
 'supplier_code' varchar(10) NOT NULL,
 'name' varchar(64) NOT NULL,
 'vat_registration_number' varchar(20) NOT NULL,
 'contact_name' varchar(64) DEFAULT NULL,
 'email_address' varchar(255) DEFAULT NULL,
 'phone_number' varchar(13) DEFAULT NULL,
 'address' varchar(64) DEFAULT NULL,
 'suburb' varchar(64) DEFAULT NULL,
 'city' varchar(64) DEFAULT NULL,
 'zip' varchar(10) DEFAULT NULL,
 'deleted' enum('0','1') NOT NULL DEFAULT '0',
 PRIMARY KEY ('id')
) ENGINE=InnoDB AUTO_INCREMENT=15 DEFAULT CHARSET=latin1


CREATE TABLE 'warehouses' (
 'id' int(11) NOT NULL AUTO_INCREMENT,
 'name' varchar(65) NOT NULL,
 'disabled' enum('0','1') NOT NULL DEFAULT '0',
 'deleted' enum('0','1') NOT NULL DEFAULT '0',
 PRIMARY KEY ('id')
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1


CREATE TABLE 'stock_items' (
 'id' int(11) NOT NULL AUTO_INCREMENT,
 'supplier_id' int(11) NOT NULL,
 'stock_code' varchar(10) NOT NULL,
 'description' varchar(255) NOT NULL,
 'type' enum('product','service') NOT NULL,
 'selling_price' decimal(19,2) NOT NULL DEFAULT '0.00',
 'inclusive_vat' enum('0','1') NOT NULL,
 'barcode' varchar(15) DEFAULT NULL,
 'deleted' enum('0','1') NOT NULL DEFAULT '0',
 PRIMARY KEY ('id')
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=latin1


CREATE TABLE 'stock' (
 'id' int(11) NOT NULL AUTO_INCREMENT,
 'stock_item_id' int(11) NOT NULL,
 'warehouse_id' int(11) NOT NULL,
 'supplier_invoice_id' int(11) NOT NULL,
 'quantity' int(11) NOT NULL,
 'cost_price' decimal(19,2) NOT NULL DEFAULT '0.00',
 'deleted' enum('0','1') NOT NULL DEFAULT '0',
 PRIMARY KEY ('id')
) ENGINE=InnoDB AUTO_INCREMENT=12 DEFAULT CHARSET=latin1

我当前的查询：

SELECT 
    stock.id,
    stock_items.stock_code,
    GROUP_CONCAT(warehouses.name ORDER BY warehouses.id) as warehouse,
    GROUP_CONCAT(stock.quantity ORDER BY warehouses.id) as stock_in_warehouse
FROM stock 
LEFT JOIN stock_items ON stock_items.id = stock.stock_item_id
LEFT JOIN warehouses ON warehouses.id = stock.warehouse_id
WHERE stock_items.deleted='0' 
GROUP BY stock.stock_item_id

给我输出

id | stock_code | warehouse | stock_in_warehouse

1 | MIKHAPLITE | One,One,Two | 4,5,2

我需要GROUP_CONCAT() as warehouse至GROUP BY(warehouses.id)和GROUP_CONCAT() as stock_in_warehouse至SUM(stock.quantity)，以便输出看起来像：

id | stock_code | warehouse | stock_in_warehouse

1 | MIKHAPLITE | One,Two | 9,2

我曾尝试使用其他帖子/论坛中提到的CAST（）和其他here中提到的方法，但似乎无法获得我想要做的事情。

任何帮助将不胜感激。

Answer 1

似乎我找到了我要查找的查询：

SELECT
    der.stock_code,
    der.description,
    der.type,
    der.selling_price,
    der.inclusive_vat,
    der.barcode,
    GROUP_CONCAT(der.warehouse) warehouse,
    GROUP_CONCAT(der.stock_in_warehouse) stock_in_warehouse
FROM (
    SELECT
        der.stock_code,
        der.description,
        der.type,
        der.selling_price,
        der.inclusive_vat,
        der.barcode,
        der.warehouse,
        SUM(der.stock_in_warehouse) stock_in_warehouse
    FROM (
        SELECT  
            stock_items.stock_code, 
            stock_items.description,
            stock_items.type,
            stock_items.selling_price,
            stock_items.inclusive_vat,
            stock_items.barcode,
            stock.quantity as stock_in_warehouse, 
            warehouses.name as warehouse 
        FROM stock
            LEFT JOIN stock_items ON stock_items.id = stock.stock_item_id
            LEFT JOIN warehouses ON warehouses.id = stock.warehouse_id
            WHERE stock_items.deleted='0' 
            ORDER BY 
                stock.id,
                warehouses.id
    ) der
    GROUP BY
        der.stock_code,
        der.warehouse
    ORDER BY 
        der.warehouse
) der
GROUP BY
    der.stock_code
ORDER BY
    der.warehouse

GROUP_CONCAT（）和GROUP BY中的SUM（）

1 个答案: