因此,我尝试将变量放入标签x ...中,以便当变量更改时,标签开始移动。
但是问题是,当我按下“下一步”按钮时,变量不会更改其值,而是保持在“ 0”
需要帮助:
import tkinter as tk
from docx import Document
HEIGHT = 500
WIDTH = 600
root = tk.Tk()
canvas = tk.Canvas(root, height=HEIGHT, width=WIDTH)
canvas.pack()
nextt=tk.IntVar()
nextt=0 #setup the nextt variable
label1 = tk.Label(text='example:')
label1.place(x=90+nextt,y=50) #put the variable here to affect position
def next2():
nextt=300
button2 = tk.Button(text="Next", font=40, command=next2)
button2.place(x=230, y=440)
#when pressing this button,variable nextt should change to 300, but it doesnt
root.mainloop()
我已经尝试过使用nextt.set = 300和/或nextt.get(),所有可能的组合...
答案 0 :(得分:0)
lastScrollPosition
中的 nextt
是局部变量,您可以尝试将标签放在函数内部:
next2
如果以后要def next2():
label1.place(x = 390, y = 50)
,则将place
用作全局变量(顺便说一句不是很好的解决方案):
nextt
仅更改def next2():
global nextt
nextt = 300
# more code
# ...
label1.place(x = 90 + nextt, y = 50)
不会自动放置标签,您必须在代码中的其他位置再次放置。