Question

我需要在PHP中使用此URL（如下）以获取API响应。每次尝试使用它时，都会收到错误消息“ HTTP 400：错误的请求（无法从参数创建定义）”，但是它可以在命令行中使用CURL进行工作。

$ch = curl_init();

$location = "'".'\{"event_type":"api_SendStore","filters":\[\{"subprop_type":"event","subprop_key":"api_response","subprop_op":"is","subprop_value":\["(none)","0"\]\},\{"subprop_type":"event","subprop_key":"country","subprop_op":"is","subprop_value":\["(none)","0"\]\}\],"group_by":\[\{"type":"event","value":"platform"\}\]\}&m=uniques&start=20190401&end=20190408&i=1'."'";

//Api connection
$url = "https://amplitude.com/api/2/events/segmentation?e={$location}";
print_r($url);

//Your username.
$username = '123456';

//Your password.
$password = '889788';

//Initiate cURL.
$ch = curl_init($url);

//Specify the username and password using the CURLOPT_USERPWD option.
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_URL, $url);

//Tell cURL to return the output as a string instead
//of dumping it to the browser.
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

//Execute the cURL request.
$response = curl_exec($ch);
print_r($response);

//Check for errors.
if(curl_errno($ch)){
    //If an error occured, throw an Exception.
    throw new Exception(curl_error($ch));
}

//Print out the response./echo $response;

$array = json_decode($response, true);
print_r($array);

这是有效的Curl命令：

curl --insecure -u API KEY:SECRET KEY 'https://amplitude.com/api/2/events/segmentation?e=\{"event_type":"api_SendStore","filters":\[\{"subprop_type":"event","subprop_key":"api_response","subprop_op":"is","subprop_value":\["(none)","0"\]\},\{"subprop_type":"event","subprop_key":"country","subprop_op":"is","subprop_value":\["(none)","0"\]\}\],"group_by":\[\{"type":"event","value":"wu_platform"\},\{"type":"event","value":"country"\}\]\}&m=uniques&start=20190401&end=20190408&i=1'

Answer 1

这不是创建URL或JSON的方法。两种都是特定的数据格式，并带有创建它们的适当工具。 http_build_query构建URL查询字符串，json_encode构建JSON。从URL中的反斜杠数量来看，您似乎正在尝试在PHP中重新创建外壳转义符。这不是必需的，当然会导致无效的URL。

<?php
$e = [
    "event_type" => "api_SendStore",
    "filters" => [
        ["subprop_type" => "event",
         "subprop_key" => "api_response",
         "subprop_op" => "is",
         "subprop_value" => ["(none)","0"],
        ],
        ["subprop_type" => "event",
         "subprop_key" => "country",
         "subprop_op" => "is",
         "subprop_value" => ["(none)","0"]
        ],
    ],
    "group_by" => [
        ["type" => "event",
         "value" => "platform",
        ]
    ]
];
$e = json_encode($e);

$query = http_build_query([
    "e" => $e,
    "m" => "uniques",
    "start" => "20190401",
    "end" => "20190408",
    "i" => "1"
]);

$url = "https://happyhappy.com/api/2/events/segmentation?$query";

echo $url;

输出：

https://happyhappy.com/api/2/events/segmentation?e=%7B%22event_type%22%3A%22api_SendStore%22%2C%22filters%22%3A%5B%7B%22subprop_type%22%3A%22event%22%2C%22subprop_key%22%3A%22api_response%22%2C%22subprop_op%22%3A%22is%22%2C%22subprop_value%22%3A%5B%22%28none%29%22%2C%220%22%5D%7D%2C%7B%22subprop_type%22%3A%22event%22%2C%22subprop_key%22%3A%22country%22%2C%22subprop_op%22%3A%22is%22%2C%22subprop_value%22%3A%5B%22%28none%29%22%2C%220%22%5D%7D%5D%2C%22group_by%22%3A%5B%7B%22type%22%3A%22event%22%2C%22value%22%3A%22platform%22%7D%5D%7D&m=uniques&start=20190401&end=20190408&i=1

此外，curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);真是愚蠢。如果您完全重视安全性，那就不要这样做。

使用PHP通过特定的URL调用API

1 个答案: