我正在尝试查找"type":"FollowEvent"的所有实例，然后在这些实例中，如果字符串"actor":后没有{，则捕获{{1 }}紧接"之后。否则，捕获"actor":之后紧跟的"中包含的字符串。
到目前为止我所拥有的：
"login:"这是什么：
对于/ path / to / dir中的所有文件，对于包含zgrep -e '"type":"FollowEvent"' /path/to/dir/* | zgrep -o '"actor":(?!{)*' | cut -f2- -d: | cut -d',' -f1 > results_file.txt
的所有行，请找到"type":"FollowEvent"，而不是"actor:"。然后在{之后和下一个:之前进行所有操作。将结果放入,。
要进行grep的文件中的一行可能看起来像这样：
results_file.txt或类似这样：
{"repo":{"url":"https://url","name":"/"},"type":"FollowEvent","public":true,"created_at":"2011-05-29","payload":{"target":{"gravatar_id":"73","id":64,"repos":35,"followers":58,"login":"username3"}},"actor":{"gravatar_id":"06","id":439,"url":"https://url","avatar_url":"https://.png","login":"username4"},"id":"14"}
我想要什么：
仅包含actor用户名的文件。在这里，我想要在{"repo":{"url":"https://url/","name":"/"},"type":"FollowEvent","public":true,"created_at":"2011-04-01","payload":{"target":{"gravatar_id":"40","repos":2,"followers":1,"login":"username2"},"actor":"username1","actor_gravatar":"de4"},"actor":{"gravatar_id":"de4","id":716,"url":"https://url","avatar_url":"https://.png","login":"username2"},"id":"12"}
中：
results_file.txt答案 0 :(得分：1)
让我们说：
JSON='{"repo":{"url":"https://url","name":"/"},"type":"FollowEvent","public":true,"created_at":"2011-05-29","payload":{"target":{"gravatar_id":"73","id":64,"repos":35,"followers":58,"login":"username3"}},"actor":{"gravatar_id":"06","id":439,"url":"https://url","avatar_url":"https://.png","login":"username4"},"id":"14"}'
对于一个简单的答案，我建议您使用jq：https://stedolan.github.io/jq/
$ echo "$JSON" | jq -r '. | select(.type=="FollowEvent") | .actor.login'
username4
您可以使用默认的程序包管理器在大多数发行版中安装它。
无论如何，如果您需要使用GNU工具。
$ echo "$JSON" | grep '"type":"FollowEvent"' | sed 's/.*"login":"\([^"]*\).*/\1/g'
username4