我编写了一个名为filterSearch的函数,该函数不受管理员保护,该函数根据多个搜索/查询参数返回资源。第一次基于状态的搜索效果很好,但是if语句中的其他搜索则无法正常工作。
这是路线
carRouter.get('/car', filterSearch, verifyToken, isAdmin, fetchAllCarAds);
这些分别是SQL查询
export const statusQuery = 'SELECT * FROM cars WHERE status = $1';
export const statusPriceQuery = 'SELECT * FROM cars WHERE status = $1 AND price >= $2 AND price <= $3';
export const statusManufacturerQuery = 'SELECT * FROM cars WHERE status = $1 manufacturer = $2';
export const bodyTypeQuery = 'SELECT * FROM cars WHERE bodytype = $1';
export const statusStateQuery = 'SELECT * FROM cars WHERE status = $1 AND (state = $2 OR state = $3)';
我使用了其他控制语句,例如if,但是仍然无法正常工作。
static async filterSearch(req, res, next) {
//console.log('req1', typeof req.query);
if (req.query.status || req.query.bodytype) {
//console.log('req2', req.query);
let { status, minprice, maxprice, bodytype, state, manufacturer } = req.query;
//console.log('req3', typeof bodytype);
try {
//status
status = status.trim().toLowerCase();
if (status && !minprice && !maxprice) {
const { rows, rowCount } = await db.query(statusQuery, ['unsold']);
if (rowCount === 0) {
return res.status(404).json({
status: 404,
error: 'Sorry, this does not exist'
});
}
return res.status(200).json({
status: 200,
data: rows
});
}
//status and price
if (status && minprice && maxprice) {
minprice = Number(minprice.trim());
maxprice = Number(maxprice.trim());
const { rows, rowCount } = await db.query(statusPriceQuery, ['unsold', minprice, maxprice]);
console.log('row', rowCount);
if (rowCount === 0) {
return res.status(404).json({
status: 404,
error: 'There is no result for your search now'
});
}
return res.status(200).json({
status: 200,
data: rows
});
}
//status and state(new/used)
if (status && state) {
state = state.trim().toLowerCase();
const { rows, rowCount } = await db.query(statusStateQuery, ['unsold', 'new', 'used']);
if (rowCount === 0) {
return res.status(404).json({
status: 404,
error: 'Search request is unavailable at the moment'
});
}
return res.status(200).json({
status: 200,
data: rows
});
}
// status and manufacturer
if (status && manufacturer) {
manufacturer = manufacturer.trim().toLowerCase();
const { rows, rowCount } = await db.query(statusManufacturerQuery, ['unsold', manufacturer]);
console.log('qui');
if (rowCount === 0) {
return res.status(404).json({
status: 404,
error: 'Something just happen right now'
});
}
return res.status(200).json({
status: 200,
data: rows
})
}
//bodyType
if (bodytype) {
//Here I get 'Cannot read property 'trim' of undefined'
bodytype = bodytype.trim().toLowerCase();
const { rows , rowCount } = await db.query(bodyTypeQuery, [bodytype]);
if (rowCount === 0) {
return res.status(404).json({
status: 404,
error: 'your search returned no result'
});
}
return res.status(200).json({
status: 200,
data: rows
});
}
return res.status(404).json({
status: 404,
error: 'There seems to be an issue with your search'
});
}
catch(error) {
return res.status(500).json({
status: 500,
error: error.message
});
}
}
next();
}
答案 0 :(得分:0)
我解决了这个问题。我要做的就是将函数分解为几个位,以适应所提供的每个查询搜索/术语。