Question

我来自C ++，并且以C＃作为新手，只需尝试一下：

class Class1
{
    int mI = 0;
    string mS = "ab";

    public static Class1 operator + (Class1 obj1, Class1 obj2)
    {
        return new Class1()
        {
            mI = obj1.mI + obj2.mI,
            mS = obj1.mS + obj2.mS
        };
    }

    public static void operator += (Class1 obj1)
    {
        mI += obj1.mI;
        mS += obj1.mS;
    }
}

我发现operator+=函数没有编译，说：

错误CS1019：应重载一元运算符。

那么C＃根本不执行这种运算符重载吗？

Answer 1

您可以像per the documentation那样重载### try to use a set ### mport random import math something = ["monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday"] correct_word = something[random.randint(0, len(something) - 1)] correct_s = set() left = 100 for s in correct_word: correct_s.add(s) gusses = len(correct_word) * 2#math.ceil(len(correct_word)/2) space = "_ " win = False guss = set() blob = "" for i in range(len(correct_word)): blob += "_ " print(blob + "GUESS LEFT: " + str(gusses)) while not win: gus = input("ENTER A LETTER: ") left = 0 if gus in correct_s: #correct_s.remove(gus) now = "" for l in correct_word: guss.add(gus) if l in guss: now += l + " " else: now += "_ " left += 1 print("GREAT!") else: gusses -= 1 now = "" for l in correct_word: if l in guss: now += l + " " else: now += "_ " left += 1 print("OOPS!") print(now + "GUESS LEFT: " + str(gusses)) if left == 0: print("CONGRATULATIONS, YOU WIN!") win = True if gusses <= 0: print("SORRY, YOU ARE OUT OF GUSSES!") print("THE RIGHT WORD IS: " + correct_word) break，但不能重载+：

赋值运算符不能显式重载。但是，当您重载二进制运算符时，相应的赋值运算符（如果有）也会隐式重载。例如，+=是使用+=求值的，该值可以重载。

因此，如您所见，+被认为是+=。这就是为什么不允许重载x = x + y运算符的原因。

C＃运算符重载是否像C ++一样支持“ + =”？

1 个答案: