Question

我有一些np.datetimes列表，我想给它们加上一个浮点数：

list_of_floats=[0.01,0.02,0.01]

list1=[np.datetime64('2016-07-01'),
       np.datetime64('2017-03-01')]

list2=[np.datetime64('2016-07-01'),
       np.datetime64('2017-03-01')]

list3=[np.datetime64('2016-07-01'),
       np.datetime64('2017-03-01')]

list_of_lists=[list1,list2,list3]

这是我尝试过的：

for i in range(len(list_of_floats)):
    list_of_lists[i].append(list_of_floats[i])

print(list_of_lists)

所需的输出：

[[np.datetime64('2016-07-01'),np.datetime64('2017-03-01'),0.01],
[np.datetime64('2016-07-01'),np.datetime64('2017-03-01'),0.02]
[np.datetime64('2016-07-01'),np.datetime64('2017-03-01'),0.01]]

我该如何克服这个问题？

Answer 1

使用enumerate

例如：

import numpy as np

list_of_floats=[0.01,0.02,0.01]

list1=[np.datetime64('2016-07-01'),
       np.datetime64('2017-03-01')]

list2=[np.datetime64('2016-07-01'),
       np.datetime64('2017-03-01')]

list3=[np.datetime64('2016-07-01'),
       np.datetime64('2017-03-01')]

list_of_lists=[list1,list2,list3]

for i, v in enumerate(list_of_floats):
    list_of_lists[i].append(v)

print(list_of_lists)

或使用zip

例如：

for i, v in zip(list_of_floats, list_of_lists):
    v.append(i)

输出：

[[numpy.datetime64('2016-07-01'), numpy.datetime64('2017-03-01'), 0.01],
 [numpy.datetime64('2016-07-01'), numpy.datetime64('2017-03-01'), 0.02],
 [numpy.datetime64('2016-07-01'), numpy.datetime64('2017-03-01'), 0.01]]

Answer 2

您可以利用zip

import numpy as np

list_of_floats=[0.01, 0.02, 0.01]
list_of_lists=[
    [np.datetime64('2016-07-01'), np.datetime64('2017-03-01')],
    [np.datetime64('2016-07-01'), np.datetime64('2017-03-01')],
    [np.datetime64('2016-07-01'), np.datetime64('2017-03-01')],
]

for date_list, float_number in zip(list_of_lists, list_of_floats):
    date_list.append(float_number)

print(list_of_lists)

将浮点数附加到日期列表

2 个答案: