Question

6月8日**

我已经更新了代码，现在它更新了数据库，如果我输入的数据相同，则会在重复错误下面触发错误，是否有可能只是说出它是重复的而不是告诉我有个大错误吗？

UPDATE clients2 SET id = :id, fullname = :fullname, paypal = :paypal, email = :email, serial_no = :serial_no, toolkitserial = :toolkitserial WHERE id = :id
SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry '11111-11111-11111-11111' for key 'serial'

因此代码几乎完整，剩下的唯一一件事就是修复复制错误。

<?php

/**
 * Use an HTML form to edit an entry in the
 * users table.
 *
 */

require "../config.php";
require "../common.php";

if (isset($_POST['submit'])) {
  if (!hash_equals($_SESSION['csrf'], $_POST['csrf'])) die();

  try {
    $connection = new PDO($dsn, $username, $password, $options);

    $user =[
      "id"        => $_POST['id'],
      "fullname" => $_POST['fullname'],
      "paypal"  => $_POST['paypal'],
      "email"     => $_POST['email'],
      "serial_no"       => $_POST['serial_no'],
      "toolkitserial"  => $_POST['toolkitserial'],

    ];

    $sql = "UPDATE clients2 
            SET id = :id, 
              fullname = :fullname, 
              paypal = :paypal, 
              email = :email, 
              serial_no = :serial_no, 
              toolkitserial = :toolkitserial

            WHERE id = :id";

  $statement = $connection->prepare($sql);
  $statement->execute($user);
  } catch(PDOException $error) {
      echo $sql . "<br>" . $error->getMessage();
  }
}
$user = array();
if (isset($_GET['id'])) {
  try {
    $connection = new PDO($dsn, $username, $password, $options);
    $id = $_GET['id'];

    $sql = "SELECT * FROM clients2 WHERE id = :id";
    $statement = $connection->prepare($sql);
    $statement->bindValue(':id', $id);
    $statement->execute();

    $user = $statement->fetch(PDO::FETCH_ASSOC);
  } catch(PDOException $error) {
      echo $sql . "<br>" . $error->getMessage();
  }
} else {
    echo "Something went wrong!";
    exit;
}
?>

<?php require "templates/header.php"; ?>

<?php if (isset($_POST['submit']) && $statement) : ?>
    <blockquote><?php echo escape($_POST['fullname']); ?> successfully updated.</blockquote>
<?php endif; ?>

<h2>Edit a user</h2>

<form method="post">
    <input name="csrf" type="hidden" value="<?php echo escape($_SESSION['csrf']); ?>">
    <?php foreach ($user as $key => $value) : ?>
      <label for="<?php echo $key; ?>"><?php echo ucfirst($key); ?></label>
        <input type="text" name="<?php echo $key; ?>" id="<?php echo $key; ?>" value="<?php echo escape($value); ?>" <?php echo ($key === 'id' ? 'readonly' : null); ?>>
    <?php endforeach; ?> 
    <input type="submit" name="submit" value="Submit">
</form>

<a href="index.php">Back to home</a>

<?php require "templates/footer.php"; ?>

能够编辑数据库文件。

Answer 1

应该像

$sql = "UPDATE clients2 
          SET fullname = :fullname, 
          paypal = :paypal, 
          email = :email, 
          serial_no = :serial_no 
        WHERE client_id = :id";

您正在使用id，但已将其更改为client_id

Answer 2

未定义变量$ user。

将$user = array();放在if (isset($_GET['id'])) {行之前

Answer 3

如果要更新，则需要知道'id'。

if(!isset($_GET['id'])) { // not set redirect to ....

$id = $_GET['id']; // if isset

然后更新。

此代码看起来不太好：如果使用OO，请使用databaseobject.class.php之类的东西，然后插入，更新，删除，按ID查找，按SQL查找..... 使用它，例如static public function find_by_id($id)。

为foreach（）提供了无效的参数-第71行

3 个答案: