Question

我正在尝试fizzbuzz程序：Why Can't Programmers.. Program?

“编写一个程序，打印从1到100的数字。但对于三个打印的倍数”Fizz“而不是数字和五个打印”Buzz“的倍数。对于三和五的倍数的数字打印“FizzBuzz”。“

protected void btn1_Click(object sender, EventArgs e)
    {
        for (int i = 1; i < 101; i++)
        {
            if (i % 3 == 0 & i % 5 == 0)
            {
                Response.Write("fizzbuzz" + ",");
            }
            else if (i % 3 == 0)
            {
                Response.Write("fizz" + ",");
            }
            else if (i % 5 == 0)
            {
                Response.Write("buzz" + ",");
            }
            else
            {
                i = i + 0;
            }

            Response.Write(i +",");
        }

    }

我能够产生某种结果，如：

1,2，嘶嘶声，3,4-，嗡嗡声，5，嘶嘶声，6,7,8，嘶嘶声，9，嗡嗡声，10,11，嘶嘶声，12,13,14，fizzbuzz，15,16,17 ，嘶嘶声，18,19，嗡嗡声，20％，嘶嘶声，21,22,23，嘶嘶声，24，嗡嗡声，25,26，嘶嘶声，27,28,29，fizzbuzz，30,31,32，嘶嘶声，33,34 ，嗡嗡声，35，fizz，36,37,38，fizz，39等等。

打印了 fizz 这个词，但它没有替换3并且 fizzbuzz 被打印但是它没有替换15，所以......

Answer 1

无论您是否符合if条件，您仍然会在代码末尾打印i。

专门查看你的for循环：

for (int i = 1; i < 101; i++)         
{             
if (i % 3 == 0 & i % 5 == 0)             
{                 
Response.Write("fizzbuzz" + ",");             
}             
else if (i % 3 == 0)             
{                 
Response.Write("fizz" + ",");             
}             
else if (i % 5 == 0)             
{                 
Response.Write("buzz" + ",");             
}             
else             
{                 
i = i + 0;             
}              
Response.Write(i +",");   //look here you print i
}

所以你需要移动最后一个Response.Write（i +“，”）;在最后else条件下。找到这些错误的最简单方法是使用调试器并调试程序。然后，您将轻松查看输出结果。所以肯定使用调试器并设置断点/手表并观察会发生什么。您的代码应更改为：

  for (int i = 1; i < 101; i++)         
    {             
    if (i % 3 == 0 & i % 5 == 0)             
    {                 
    Response.Write("fizzbuzz" + ",");             
    }             
    else if (i % 3 == 0)             
    {                 
    Response.Write("fizz" + ",");             
    }             
    else if (i % 5 == 0)             
    {                 
    Response.Write("buzz" + ",");             
    }             
    else             
    {                 
    Response.Write(i +",");   //look here you print i
    }              
    }

请注意，删除i=i+1您的for循环已经通过递增i来处理此问题。

编辑

不确定这是否更容易，但这是使用lambda的另一种方法：

            List<int> t;
            t = Enumerable.Range(1, 100).ToList();

            var fizzBuzz = t.Where(num => num % 3 == 0 && num % 5 == 0);
            var fizz = t.Where(num => num % 3 == 0);
            var buzz = t.Where(num => num % 5 == 0);
            var notFizzBuzz = t.Where(num => num % 3 != 0 && num % 5 !=0);

            //print fizzBuzz elements
            Console.WriteLine("Printing fizzBuzz elements...");
            foreach (int i in fizzBuzz)
                Console.WriteLine(i);

            //print fizz elements
            Console.WriteLine("Printing fizz elements...");
            foreach (int i in fizz)
                Console.WriteLine(i);

            //print buzz elements
            Console.WriteLine("Printing buzz elements...");
            foreach (int i in buzz)
                Console.WriteLine(i);

            //print other elements
            Console.WriteLine("Printing all others...");
            foreach (int i in notFizzBuzz)
                Console.WriteLine(i);

Answer 2

尝试这些更改

protected void btn1_Click(object sender, EventArgs e)
{
    for (int i = 1; i < 101; i++)
    {
        if (i % 3 == 0 & i % 5 == 0)
        {
            Response.Write("fizzbuzz" + ",");
        }
        else if (i % 3 == 0)
        {
            Response.Write("fizz" + ",");
        }
        else if (i % 5 == 0)
        {
            Response.Write("buzz" + ",");
        }
        else
        {
            Response.Write(i +",");
        }           
    }
}

你的i = i + 0显然什么也没做，因为你在i的值上加0。

你打算将数字打印到响应中，无论if / else块的结果是什么（它放在它之后），所以它应该被移动到else中（意味着只有if才打印，否则如果不匹配）

Answer 3

将Response.Write(i +",");移至您的最终其他

Answer 4

protected void btn1_Click(object sender, EventArgs e)
{
    for (int i = 1; i < 101; i++)
    {
        if (i % 3 == 0 & i % 5 == 0)
        {
            Response.Write("fizzbuzz" + ",");
        }
        else if (i % 3 == 0)
        {
            Response.Write("fizz" + ",");
        }
        else if (i % 5 == 0)
        {
            Response.Write("buzz" + ",");
        }
        else
        {
            i = i + 0; //this is totally useless
            Response.Write(i + ",");

        }

        //Response.Write(i +","); //This will always write the number, even if you wrote fizz or buzz
    }

}

Answer 5

另一个简单的实现：

for (int i = 1; i <= 100; i++)
        {
            Console.WriteLine((i % 3 == 0) ? ((i % 5 == 0) ? "FizzBuzz" : "Fizz") : ((i % 5 == 0) ? "Buzz" : i.ToString()));
        }
Console.ReadKey();

Answer 6

    public static void PrintMod3And5FromInterval(int start, int end)
    {
        if (end < start)
        {
            Console.WriteLine("End number should be higher than start.");
        }
        else
        { 
            string result = "";
            for (int x = start; x <= end; x++)
            {
                if (x % 3 == 0)
                    result += "fizz";
                if (x % 5 == 0)
                    result += "buzz";
                if (result == "")
                    Console.WriteLine(x);
                else
                    Console.WriteLine(result);
                result = "";
            }
        }
    }
    static void Main(string[] args)
    {
        PrintMod3And5FromInterval(1, 100);
        Console.Read();
    }

Answer 7

这是我最初的解决方法...

setCookieFunc

但是这个要短得多...

app.get('/api/addtocart', async (req, res) => {
  try {
    const productId = parseInt(req.query.productId);
    const quantity = parseInt(req.query.quantity);
    const sessionData = req.headers['session-data'];
    const headers = {};
    if (sessionData) headers.Cookie = sessionData;
    const response = await axios.post(`${WP_API}/wc/v2/cart/add`, {
      product_id: productId,
      quantity
    }, { headers });
    if (!sessionData) {
      const cookies = response.headers['set-cookie'];
      const setCookieFunc = (cookie) => {
        const [cookieKeyValue, ...cookieOptionsArr] = cookie.split('; ');
        const cookieKey = cookieKeyValue.split('=')[0];
        const cookieValue = decodeURIComponent(cookieKeyValue.split('=')[1]);
        const cookieOptions = { };
        cookieOptionsArr.forEach(option => (cookieOptions[option.split('=')[0]] = option.split('=')[1]));
        if (cookieOptions.expires) {
          const expires = new Date(cookieOptions.expires);
          cookieOptions.expires = expires;
        }
        res.cookie(cookieKey, cookieValue, cookieOptions);
      };
      cookies.map(cookie => setCookieFunc(cookie));
    }
    return res.json(response.data);
  } catch (error) {
    // Handle error
    return res.json(error);
  }
});

打印数字从1到100并用字符串替换一些（fizzbuzz）

7 个答案:

编辑