Question

php函数遍历对象数组并列出其标题。我有一个打开模式的链接。当我按详细信息时，如何从$ results中动态加载关于对象$ r的模式标题和正文。

<?php
foreach ($results as $r) {
?>
<div class="row justify-content-center">
    <div class="alert alert-success">
        <strong>
            <?php echo $r['_source']['title']; ?></strong> <span id="showSearchTerm"></span></br>
        <a data-target="#myModal" data-toggle="modal" class="MainNavText" id="MainNavHelp" href="#myModal">Details</a>
    </div>
</div>
<!-- Modal -->
<div id="myModal" class="modal fade" role="dialog">
    <div class="modal-dialog">
        <!-- Modal content-->
        <div class="modal-content">
            <div class="modal-header">
                <!-- <button type="button" class="close" data-dismiss="modal">&times;</button> -->
                <h2 class="modal-title">
                    <?php echo $r['_source']['title']; ?>
                </h2>
            </div>
            <div class="modal-body">
                <p>
                    <?php echo $r['_source']['body']; ?>
                </p>
                <p>
                    <?php echo $r['_source']['path']['real']; ?>
                </p>
            </div>
            <div class="modal-footer">
                <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
            </div>
        </div>
    </div>
</div>
<?php

}

Answer 1

从ajax调用中获取填写模态所需的信息。之后，您可以使用以下内容添加该内容：

$(".classname").append(information_from_ajax_call_stored_in_variable);

动态加载对象数组以模式方式查看它们

1 个答案: