Question

我们的从属表中的一个仅在每月的第三天提供，我需要在前两天编写一个查询，该查询应检查从第3个病房获得的当前月份数据。

尝试了CASE表达式，该表达式不起作用

select case when datepart(day, getdate()) <= 2 
            then (select * from T1 where date in (201904,201903))
            else (select * from T1 where date in (201905,201904))
       end

我知道我的方法是错误的，需要帮助才能达到我的要求。

Answer 1

有点猜测，但是像这样？

SELECT {Columns}
FROM {Your Table} YT
WHERE YourDateColumn >= DATEADD(MONTH, DATEDIFF(MONTH, 0, DATEADD(DAY, -2, GETDATE())),0)
  AND YourDateColumn < DATEADD(MONTH, DATEDIFF(MONTH, 0, DATEADD(DAY, -2, GETDATE()))+1,0);

Answer 2

无论是否在前三天内，您都可以使用它来“标记”。它的格式设置为将日期看成INT。

DECLARE @Currentday AS INT

SET @Currentday = cast(replace(cast(GETDATE() AS DATE), '-', '') AS INT)

IF @Currentday BETWEEN cast(replace(cast(DATEADD(month, DATEDIFF(month, 0, getdate()), 0) AS DATE), '-', '') AS INT)
        AND cast(replace(cast(DATEADD(month, DATEDIFF(month, 0, getdate()), 2) AS DATE), '-', '') AS INT)
    -- if within first 3 days
    SELECT 1 --insert your own statement
ELSE
    -- if not within first 3 days
    SELECT 2 --insert your own statement

基于getdate的动态日期更改

2 个答案: