Django |制作搜索表单以使用多种模型进行过滤

Question

我正在尝试在Django项目中创建一个搜索表单，该表单将过滤多个模型（3）。该表单适用于单个模型以及由外键绑定的其他模型。但是，我无法将不同模型的查询组合到一个get_queryset。

forms.py

class SearchForm(forms.Form):
username=forms.CharField(
    label = 'enterprise_id',
    required = False    
)
skill_name=forms.ModelChoiceField(
    queryset=Skill_name.objects,
    label='skill_list',
    required=False
)

model.py

    class EnterpriseID(models.Model):
    enterprise_id = models.CharField('enterprise_id',max_length=40,blank=True,default="",)
    def __str__(self):
        return self.enterprise_id

class Skill_name(models.Model):
    skill_name = models.CharField('skill_name',max_length=40,blank=False,null=False,)
    def __str__(self):
             return '{0}'.format(self.skill_name)

class Skill(models.Model):
    enterprise_id = models.ForeignKey(EnterpriseID,verbose_name="enterprise_id",on_delete=models.PROTECT,)
    skill_name=models.ForeignKey(Skill_name,verbose_name="skill_name",on_delete=models.PROTECT,)
    def __str__(self):
             return '{0}'.format(self.enterprise_id)

class Employee(models.Model):
    # user = models.OneToOneField(accounts_models.AuthUser, on_delete=models.CASCADE, blank=True)
    enterprise_id = models.ForeignKey(EnterpriseID,verbose_name="enterprise_id",on_delete=models.PROTECT,)

    join_at = models.DateField('join_at',default="",null=True,blank=True)
    def __str__(self):
        return '{0}'.format(self.enterprise_id)

views.py

class PersonalInfoSearchView(LoginRequiredMixin,ListView):
    model = Employee
    template_name = 'personal_info/search_personal_info.html'
    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs) 
        context['form'] = SearchForm(self.request.GET) 
        return context

    def get_queryset(self):
        form = SearchForm(self.request.GET)
        queryset = super().get_queryset()
        if form.is_valid():

            username = form.cleaned_data['username']   
            skill_name = form.cleaned_data['skill_name']

            if username:

                queryset=queryset.filter(enterprise_id__enterprise_id__icontains=username)

            if skill_name:
               skill_query =Skill.objects.filter(skill_name=skill_name)     
         return queryset.distinct()