Question

我使用for循环对列表进行洗牌并将其附加到另一个空列表（列表A）。我可以看到每个改组后的列表都是不同的，但列表A仅附加了最后一个改组后的列表的多个。

print('---------shuffle list-------------------------------------')
matr=[   ] 

entry=[1, 2, 3, 4, 5, 6, 7, 8, 9]

for i in range(9):
    shuffle(entry )
    print(entry )
    matr.append(entry)

print(matr)

'''
results below:
---------shuffle list-------------------------------------
[3, 1, 7, 5, 8, 9, 2, 6, 4]
[5, 4, 6, 8, 1, 9, 7, 2, 3]
[6, 4, 7, 5, 1, 3, 2, 9, 8]
[4, 9, 8, 1, 7, 3, 6, 5, 2]
[5, 1, 9, 2, 8, 6, 4, 7, 3]
[3, 5, 1, 4, 2, 6, 8, 9, 7]
[1, 2, 4, 6, 7, 8, 3, 9, 5]
[4, 8, 1, 6, 7, 3, 5, 9, 2]
[6, 4, 2, 1, 9, 8, 3, 5, 7]

[[6, 4, 2, 1, 9, 8, 3, 5, 7], [6, 4, 2, 1, 9, 8, 3, 5, 7], [6, 4, 2, 1, 9, 8, 3, 5, 7], [6, 4, 2, 1, 9, 8, 3, 5, 7], [6, 4, 2, 1, 9, 8, 3, 5, 7], [6, 4, 2, 1, 9, 8, 3, 5, 7], [6, 4, 2, 1, 9, 8, 3, 5, 7], [6, 4, 2, 1, 9, 8, 3, 5, 7], [6, 4, 2, 1, 9, 8, 3, 5, 7]]

'''

它应该在每个改组列表的后面附加最后一个改组的列表。

Answer 1

它们是相同的对象，所以您必须这样做，shuffle是例外，您需要这样做：

matr=[] 

entry=[1, 2, 3, 4, 5, 6, 7, 8, 9]

for i in range(9):
    entry = entry.copy()
    shuffle(entry)
    print(entry)
    matr.append(entry)

print(matr)

输出：

[9, 7, 6, 4, 3, 2, 8, 5, 1]
[4, 3, 2, 8, 7, 1, 5, 9, 6]
[3, 9, 7, 4, 5, 8, 2, 1, 6]
[6, 1, 9, 5, 2, 3, 4, 7, 8]
[5, 4, 7, 9, 8, 2, 6, 3, 1]
[2, 3, 5, 8, 6, 7, 9, 4, 1]
[5, 4, 9, 8, 3, 6, 1, 7, 2]
[5, 1, 2, 3, 7, 8, 6, 9, 4]
[6, 8, 9, 2, 1, 5, 3, 7, 4]
[[9, 7, 6, 4, 3, 2, 8, 5, 1], [4, 3, 2, 8, 7, 1, 5, 9, 6], [3, 9, 7, 4, 5, 8, 2, 1, 6], [6, 1, 9, 5, 2, 3, 4, 7, 8], [5, 4, 7, 9, 8, 2, 6, 3, 1], [2, 3, 5, 8, 6, 7, 9, 4, 1], [5, 4, 9, 8, 3, 6, 1, 7, 2], [5, 1, 2, 3, 7, 8, 6, 9, 4], [6, 8, 9, 2, 1, 5, 3, 7, 4]]

随机播放列表，然后将其附加到另一个列表

1 个答案: