Question

我脑子里有个解决问题的办法，但是我不太知道如何用代码来解决。我陷入了在Java方法中调用方法的麻烦。

我有此代码：

public Student getStudent(String queryWord){
    //the queryWord here should actually be the String result that returnQueryColumn returns

}

private static Map<String, String> returnMap(String myQuery){
    String[] params = myQuery.split("=");
    Map<String, String> myMap = new HashMap<String, String>();
    String myKey = params[0];
    String myValue = params[1];

    //myKey should be for example firstName, myValue should be the ACTUAL first name of the student
    myMap.put(myKey,myValue);

    return myMap;
}

private static String returnQueryColumn(Map<String, String> myMap){
    //here I want to get just the KEY from the myMap(from the returnMap method)
    //that key should be the column in my database, so I need this so that later on I can compare if the given key (firstName) is present in the database as a column

    String queryWord = returnMap().get(); //query should get firstName in my case

    return queryWord;
}

我知道这段代码行不通，但是我需要一些帮助，我如何才能实现自己的想法？我陷入了困境-我如何才能在其他方法中调用一个方法，并使第一个方法中返回的字符串成为第二个方法中的参数。

Answer 1

假设您有Student个课程：

public class Student {
    String fullName;

    public Student(String fullName) {
        this.fullName = fullName;
    }
}

如果我正确理解了您的意图，Main班级可能看起来像这样。

示例代码显示学生的fullName属性。

public class Main {

    public static void main(String[] args) {
        Student student = getStudent("john=John Appleseed");
        System.out.println(student.fullName);
    }

    public static Student getStudent(String myQuery) {
        return returnQueryColumn(myQuery);
    }

    private static Map<String, Student> returnMap(String myQuery){
        String[] params = myQuery.split("=");
        Map<String, Student> myMap = new HashMap<String, Student>();
        String myKey = params[0];
        String myValue = params[1];
        Student student = new Student(myValue);
        myMap.put(myKey, student);

        return myMap;
    }

    private static Student returnQueryColumn(String myQuery) {
        String[] params = myQuery.split("=");
        String key = params[0];
        return returnMap(myQuery).get(key);
    }
}

在Java中使用其他方法调用带有参数的方法

1 个答案: