Question

我正在尝试制作一个bash脚本，该脚本在执行时会根据日期是否在一定范围内运行一组不同的命令。我只关心检查日期和月份。

例如：假设我想要一个脚本，该脚本根据欧洲日历告诉我该季节。我将以以下格式为它提供4段代码：

if date is between 01-03 and 01-06 then
    echo "It is spring"
if date is between 01-06 and 01-09 then
    echo "It is summer"
if date is between 01-09 and 01-12 then
    echo "It is autumn"
if date is between 01-12 and 01-03 then
    echo "It is winter"

使用date命令当然可以实现。我只是不确定如何在有效的公式中使用月和日数字来检查此类范围。

Answer 1

javac 1.8.0_212指定一种格式，仅将date +%m输出月份号，因此您可以在自己的条件下使用该格式：

date

Answer 2

使用case语句来匹配由固定格式的月份和日期组成的单个字符串。

Google Drive

Answer 3

我发现，对于我所需要的，我可以简单地估计是本月的上半月还是下半月。我使用此检查成功创建了一个工作脚本：

current_month=$(date +%m)
current_day=$(date +%d)

if (( current_month == 1 )) && (( current_day < 16 ))
then
    # January, first half
    echo "January, first half"
elif (( current_month == 1 )) && (( current_day >= 16 ))
then
    # January, second half
    echo "January, second half"
elif (( current_month == 2 )) && (( current_day < 16 ))
then
    # February, first half
    echo "February, first half"
elif (( current_month == 2 )) && (( current_day >= 16 ))
then
    # February, second half
    echo "February, second half"
elif (( current_month == 3 )) && (( current_day < 16 ))
then
    # March, first half
    echo "March, first half"
elif (( current_month == 3 )) && (( current_day >= 16 ))
then
    # March, second half
    echo "March, second half"
elif (( current_month == 4 )) && (( current_day < 16 ))
then
    # April, first half
    echo "April, first half"
elif (( current_month == 4 )) && (( current_day >= 16 ))
then
    # April, second half
    echo "April, second half"
elif (( current_month == 5 )) && (( current_day < 16 ))
then
    # May, first half
    echo "May, first half"
elif (( current_month == 5 )) && (( current_day >= 16 ))
then
    # May, second half
    echo "May, second half"
elif (( current_month == 6 )) && (( current_day < 16 ))
then
    # June, first half
    echo "June, first half"
elif (( current_month == 6 )) && (( current_day >= 16 ))
then
    # June, second half
    echo "June, second half"
elif (( current_month == 7 )) && (( current_day < 16 ))
then
    # July, first half
    echo "July, first half"
elif (( current_month == 7 )) && (( current_day >= 16 ))
then
    # July, second half
    echo "July, second half"
elif (( current_month == 8 )) && (( current_day < 16 ))
then
    # August, first half
    echo "August, first half"
elif (( current_month == 8 )) && (( current_day >= 16 ))
then
    # August, second half
    echo "August, second half"
elif (( current_month == 9 )) && (( current_day < 16 ))
then
    # September, first half
    echo "September, first half"
elif (( current_month == 9 )) && (( current_day >= 16 ))
then
    # September, second half
    echo "September, second half"
elif (( current_month == 10 )) && (( current_day < 16 ))
then
    # October, first half
    echo "October, first half"
elif (( current_month == 10 )) && (( current_day >= 16 ))
then
    # October, second half
    echo "October, second half"
elif (( current_month == 11 )) && (( current_day < 16 ))
then
    # November, first half
    echo "November, first half"
elif (( current_month == 11 )) && (( current_day >= 16 ))
then
    # November, second half
    echo "November, second half"
elif (( current_month == 12 )) && (( current_day < 16 ))
then
    # December, first half
    echo "December, first half"
elif (( current_month == 12 )) && (( current_day >= 16 ))
then
    # December, second half
    echo "December, second half"
else
    # Error
    echo "Error: Invalid date"
fi

Answer 4

这是您发布的答案的简单得多的版本：

read -r current_month current_day <<< $(date '+%B %d')

if (( current_day < 16 ))
then
    half=first
else
    half=second
fi

echo "$current_month, $half half"

今天的输出：

June, first half

%B格式的代码提供了本地的当前完整月份名称。使用read同时获取两个值可以避免罕见的问题，即在月份的最后一天的午夜恰好获取不同月份的日期。

此脚本通过使用该格式字符串并逐段构建要输出的字符串来删除lot of repetition。

十行与103行。

重击：根据日期执行不同的功能

4 个答案: