我有12个单选按钮。当我单击提交时,POST方法的变量为空,我试图使用get方法,但是它不起作用。
<div class="tab-pane" id="q2">
<h4 class="info-text"> يرحب بالمناقشة ويتقبل وجهة النظر الاخرى من الطلبة</h4>
<div class="row">
<div class="col-sm-10 col-sm-offset-1">
<div class="col-sm-4">
<div class="choice" data-toggle="question2">
<input type="radio" class="form-control" name="qqq2" value="1">
<div class="icon">
<i class="fa fa-thumbs-o-up"></i>
</div>
<h4>نعم</h4>
</div>
</div>
<div class="col-sm-4">
<div class="choice" data-toggle="question2">
<input type="radio" name="qqq2" class="form-control" value="2">
<div class="icon">
<i class="fa fa-hand-paper-o"></i>
</div>
<h4>نوعاً ما</h4>
</div>
</div>
<div class="col-sm-4">
<div class="choice" data-toggle="question2">
<input type="radio" name="qqq2" class="form-control" value="3">
<div class="icon">
<i class="fa fa-thumbs-o-down"></i>
</div>
<h4>لا</h4>enter code here
</div>
</div>
</div>
</div>
</div>
这是php的代码
if (isset($_POST['finish'])) {
$barcode = $_POST['barcode'];
$q1 = $_POST['question'];
$q2 = $_POST['qqq2'];
$q3 = $_POST['qqq3'];
$q4 = $_POST['qqq4'];
$q5 = $_POST['qqq5'];
$q6 = $_POST['qqq6'];
$q7 = $_POST['qqq7'];
$q8 = $_POST['qqq8'];
$q9 = $_POST['qqq9'];
$q10 = $_POST['qqq10'];
$q11 = $_POST['qqq11'];
$q12 = $_POST['qqq12'];
echo $inSql = "INSERT INTO `quesAnswers`( `barcode`, `q1`, `q2`, `q3`, `q4`, `q5`, `q6`, `q7`, `q8`, `q9`, `q10`, `q11`, `q12`)
values ( '$barcode', '$q1', '$q2', '$q3', '$q4', '$q5', '$q6', '$q7', '$q8', '$q9', '$q10', '$q11', '$q12') ";
$inQuery = mysqli_query($con, $inSql) or die(mysqli_error($con));
}