Question

我打算做的是：首先验证表格，然后处理是否满足某些条件。我已粘贴下面的代码原型。我已经交叉检查了任何轻微/愚蠢的错误。感谢

代码：

<form id = "myform" action = process.php method = 'post'>
//some form elements here
<input type="submit" value="Submit this form"onclick="validate();return false;" />
</form>

<script type="text/javascript">
function validate(){
if(validated) myform.submit();
else Alert(Some message); 
</script>
}

Answer 1

我认为你需要做这样的事情：

<form id="myform" action="process.php" method="post" onsubmit="return validate();">
//some form elements here
<input type="submit" value="Submit this form" />
</form>

<script type="text/javascript">
function validate(){
    ...
    if(!valid)
        alert('Error');
    return valid;
}
</script>

通过javascript验证后的html-php表单提交

1 个答案: