我正在使用板条箱服务器和android客户端 但是线程不会被android客户端打断 我的Android客户端从服务器请求了RoomList 和服务器接收,客户端接受 并使用适配器填写我的ListView 如果点击后退按钮,这是一个问题, 比RoomListAcitivity关闭并且线程已停止 但是线程并没有在我的应用程序中存活下来 首先Enter已成功进行 但按下BackButton并重新输入此活动 MyApp只是白色,没有动作 我如何才能停止该线程? (并对我的英语水平感到抱歉...)
我尝试了.interrupt()方法和handler.removeMessages(0) 但是失败的线程仍然存在
上传完整的Java代码,以防万一...
ListView roomList;
RoomAdapter roomAdapter;
Socketservice ss;
String msg,rtitle;
String msgs[];
String list[];
Thread listthread,EnterRoomThread,removeV;
boolean staterun = true;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_list_room);
roomList = findViewById(R.id.roomList);
roomAdapter = new RoomAdapter();
listthread = new Thread() {
public void run(){
ss.out.println("163|");
ss.out.println("100|");
try {
while (staterun == true) {
msg = ss.in.readLine();
handler.post(new Runnable() {
public void run() {
msgs = msg.split("\\|");
String protocol = msgs[0];
switch (protocol) {
case "163":
list = msgs[1].split(",");
for (int i = 0; i < list.length; i++) {
String list1[] = list[i].split("-");
String listT = list1[0];
int listC = Integer.parseInt(list1[1]);
int listI = Integer.parseInt(list1[2]);
roomAdapter.CreateRoom(listI, listT, listC);
}
roomList.setAdapter(roomAdapter);
msg = "";
msgs = null;
break;
case "200":
Intent i = new Intent(getApplicationContext(), GameWaitingActivity.class);
i.putExtra("tname", rtitle);
staterun = !staterun;
Toast.makeText(getApplicationContext(),""+listthread.isAlive(),Toast.LENGTH_SHORT).show();
startActivity(i);
finish();
break;
case "201":
Toast.makeText(getApplicationContext(), "방이 꽉 찼습니다.", Toast.LENGTH_SHORT).show();
break;
}
}
});
}
} catch (IOException e) {
}
}
};
listthread.start();
roomList.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
Room item = (Room) roomList.getItemAtPosition(position);
rtitle=item.getTitle();
EnterRoomThread = new Thread() {
public void run() {
ss.out.println("200|" + rtitle);
EnterRoomThread.interrupt();
}
};
EnterRoomThread.start();
}
});
}
Handler handler = new Handler();
@Override
public void onBackPressed() {
removeV = new Thread() {
public void run(){
ss.out.println("101|");
removeV.interrupt();
}
};
removeV.start();
handler.removeMessages(0);
staterun = false;
listthread.interrupt();
Toast.makeText(getApplicationContext(),""+listthread.isAlive(),Toast.LENGTH_SHORT).show();
finish();
}
}
答案 0 :(得分:0)
继续进行,在run()方法中编写
//use this boolean value to keep track.
boolean shouldRunFlag = true;
while (shouldRunFlag) {
try {
Thread.sleep(10);
//Do your work............
} catch (Exception e) {
e.printStackTrace();
Log.v(TAG, "Interrupted Exception caught");
// change the flag, so that while loop can be broken.
shouldRunFlag = false;
Log.v(TAG, "run: breaking the loop");
break;
}
}
这就是您中断和清洁线程的方式
private void interrupt(Thread currentThread) {
Log.i(TAG, "interrupt");
if (currentThread != null) {
Thread dummyThread = currentThread;
dummyThread.interrupt();
currentThread = null;
}
}