Question

这是我得到的错误

SQLSTATE [42000]：语法错误或访问冲突：1064您的SQL语法有一个错误；请参见语法。请查看与您的MariaDB服务器版本相对应的手册，以在“ anish123@gmail.com”附近使用正确的语法。第2行中的GROUP BY email，date'（SQL：SELECT email，date，min（time）AS checkin，max（time）AS checkout，（（（TIME_TO_SEC（TIMEDIFF（max（time），min（time））））/ 60 ）/ 60）区别↵来自个人资料WHERE'。1 = 1和类似'anish123@gmail.com'的电子邮件。'GROUP BY电子邮件，日期）“

我正在尝试根据提供的电子邮件和单击按钮来过滤数据。第一个查询运行正常，但是当我尝试在第二个查询中使用相同的where条件时出现错误。

$post = $request->all();
$email = $request->input('email');
$cond = ' 1=1 ';
if(!empty($post['email'])){
    $cond .= " and email like '".$post['email']."'";
}
$qry = 'SELECT User_id, email, status, date, time FROM profile WHERE '.$cond.' ';
$data = DB::select($qry);

$sql=" SELECT email, date, min(time) AS checkedin, max(time) AS checkedout,( (TIME_TO_SEC(TIMEDIFF(max(time), min(time))) / 60) / 60) difference
    FROM profile WHERE '.$cond.' GROUP BY email, date";
    $previousdata = DB::select($sql);

Answer 1

您为$sql使用了错误的字符串连接：

$sql=" SELECT email, date, min(time) AS checkedin, max(time) AS checkedout,( (TIME_TO_SEC(TIMEDIFF(max(time), min(time))) / 60) / 60) difference
    FROM profile WHERE " . $cond . " GROUP BY email, date";

使用原始SQL，您的查询将容易受到SQL注入的攻击。 Read more about this problem。

从技术上讲，您可以将Laravels query builder用于两个语句。

$conditions = [];

if ($email) {
    $conditions[] = ['email', 'like', $email];
}

$profile = DB::table('profile')
    ->select('user_id', 'email', 'status', 'date', 'time')
    ->where($conditions)
    ->get();

$previousData = DB::table('profile')
    ->select('email', 'date', DB:raw('min(time) checkedin'), DB:raw('max(time) checkedout'), DB::raw('((TIME_TO_SEC(TIMEDIFF(max(time), min(time))) / 60) / 60) difference'))
    ->where($conditions)
    ->groupBy('email', 'date')
    ->get();

Answer 2

我已经在上面的右侧编辑了代码。错误是由于字符串串联

$sql="SELECT email, date, min(time) AS checkedin, max(time) AS checkedout,( (TIME_TO_SEC(TIMEDIFF(max(time), min(time))) / 60) / 60) difference
    FROM profile WHERE".$cond. "GROUP BY email, date";

单击按钮时，我试图根据电子邮件过滤器运行两个语句

2 个答案: