Question

我写了一个shell脚本。该行将如下所示：

"holderIdentity":"leader-elector1-5cd5b9d76d-ztfgf","numberofLeader":{"":0,"node2":1,"node3":2,"node4":2}"

字符5cd5b9d76d-ztfgf将被随机创建，因此我对grep的关键字仅为leader-elector。而且字符串,"numberofLeader":{"":0,"node2":1,"node3":2,"node4":2}"也是随机的（每次都不同）

如何仅从行中获取此字符串leader-elector1-5cd5b9d76d-ztfgf。

非常感谢您！

Answer 1

使用GNU grep

grep -Eo 'leader-elector[^"]*' <<< '"holderIdentity":"leader-elector1-5cd5b9d76d-ztfgf","numberofLeader":{"":0,"node2 ":1,"node3":2,"node4":2}"'

否则具有bash regex功能

var='"holderIdentity":"leader-elector1-5cd5b9d76d-ztfgf","numberofLeader":{"":0,"node2 ":1,"node3":2,"node4":2}"'
re='leader-elector[^"]*'

if [[ $var =~ $re ]] ; then
  declare -p BASH_REMATCH
  echo "${BASH_REMATCH[0]}"
fi

Grep Shell脚本中仅一行中的字符串

1 个答案: